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shepuryov [24]
3 years ago
5

What are the two factors that determine the period of a pendulum? acceleration of gravity and the mass of the bob mass of the bo

b and length of the string length of the string and acceleration of gravity acceleration of gravity and angle of the swing
Physics
2 answers:
V125BC [204]3 years ago
8 0
<span>The two factors which determine the period of a pendulum is:

A) Length of the string
B) Acceleration of gravity

In short, Your Answer would be Option C

Hope this helps!</span>
Artist 52 [7]3 years ago
7 0
<h3><u>Answer</u>;</h3><h3> length of the string and acceleration of gravity </h3><h3>Explanation;</h3>
  • Period, T, refers to the  time taken for one complete oscillation.
  • The period T of a pendulum is affected by the following factors;  
  1. The length of the pendulum or the length of the string; such that the longer the length of the pendulum, the longer the period.
  2. The acceleration of gravity or the gravitational field strength; such that the greater the gravitational acceleration the shorter the period.

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Magnetic fields surround magnets. They attract or repel, depending on the charge of the object in it.
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After hitting a long fly ball that goes over the right fielder's head and lands in the outfield, the batter decides to keep goin
jarptica [38.1K]

Answer:

a) 633.39 J

b) 0.28

Explanation:

a)The kinetic energy of the player = \frac{1}{2} mv^{2}

Work done by friction = energy change of the player

                                    = \frac{1}{2} 67(4.35)^{2} = 633.9 J

b) Assuming the frictional force stays constant,

Work done by friction = Frictional force×distance

Frictional force = kinetic friction(μ)×normal reaction

Normal reaction = weight = mass×gravitational acceleration ( g=10m/s2 )

Combining these equations

633.9  =  F×3.4 ⇒ F = 186.44 N

F = μmg ⇒ μ = F/mg

                     = 186.44/670

                      = 0.28

5 0
3 years ago
Your spaceship lands on an unknown planet. to determine the characteristics of this planet, you drop a 1.50 kg wrench from 5.50
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1. calculate the value of acceleration that objects gains in that period of time
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5.50*2/t^2 = a
11.00/0.657 = a
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now you got the acceleration
2. you have laws of gravitation for that

g = Gm/r^2
where g is the acceleration value
16.74 = 6.754*10^-11 × m/ 6.28*10^4
105.14*10^4 /6.754*10-11 = m
15.567*10^15 = m
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4 years ago
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Explanation:

Below is an attachment containing the solution.

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liquid helium has a very low boiling point, 4.2 k, as well as a very low latent heat of vaporization, 2.00 104 j/kg. if energy i
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4.80 \times 10^3 \text { seconds }  long does it take to boil away 2.40 kg of the liquid.

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Latent heat of vapourization $L=2.00 \times 10^4 \mathrm{~J} / \mathrm{kg}$

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mass of liquid is $m=2.40 \mathrm{~kg}$

amount of heat required to boil

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Power $p=\frac{\text { work }}{\text { time }}=\frac{\text { Energy }}{\text { Time }}$

$$\begin{aligned}P &=\frac{Q}{t} \\\text { tine } t &=\frac{Q}{P}=\frac{4.80 \times 10^4 \mathrm{~J}}{10} \\t &=4.80 \times 10^3 \text { seconds }\end{aligned}$$

The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.

The heat that is used or lost as matter melts and transitions from a solid to a fluid form at a constant temperature is known as the latent heat of fusion.

Due to the fact that during softening the heat energy anticipated to transform the substance from solid to fluid at air pressure is the latent heat of fusion and that the temperature remains constant during the process, the "enthalpy" of fusion is a latent heat. The enthalpy change of any quantity of material during dissolution is known as the latent heat of fusion.

For learn more about Latent heat of vaporization, visit: brainly.com/question/14980744

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