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shepuryov [24]
3 years ago
5

What are the two factors that determine the period of a pendulum? acceleration of gravity and the mass of the bob mass of the bo

b and length of the string length of the string and acceleration of gravity acceleration of gravity and angle of the swing
Physics
2 answers:
V125BC [204]3 years ago
8 0
<span>The two factors which determine the period of a pendulum is:

A) Length of the string
B) Acceleration of gravity

In short, Your Answer would be Option C

Hope this helps!</span>
Artist 52 [7]3 years ago
7 0
<h3><u>Answer</u>;</h3><h3> length of the string and acceleration of gravity </h3><h3>Explanation;</h3>
  • Period, T, refers to the  time taken for one complete oscillation.
  • The period T of a pendulum is affected by the following factors;  
  1. The length of the pendulum or the length of the string; such that the longer the length of the pendulum, the longer the period.
  2. The acceleration of gravity or the gravitational field strength; such that the greater the gravitational acceleration the shorter the period.

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10 points
enot [183]

Answer:

B

Explanation:

I just took the test

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When sound is created it travels to the car through a
Rasek [7]

A sound wave is a longitudinal wave caused by vibrations and carried through a substance. The particles of the substance, such as air particles, vibrate back and forth along the path that the sound waves travel. Sound is transmitted through the vibrations and collisions of the particles.

This could maybe help you with your answer.

4 0
3 years ago
Does the tension of a string affect the speed of a wave
Nata [24]
Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.
5 0
3 years ago
g An electron enters a region of space containing a uniform 1.63 × 10 − 5 T magnetic field. Its speed is 121 m/s and it enters p
kolbaska11 [484]

Answer:

i. The radius 'r' of the electron's path is 4.23 × 10^{-5} m.

ii. The frequency 'f' of the motion is 455.44 KHz.

Explanation:

The radius 'r' of the electron's path is called a gyroradius. Gyroradius is the radius of the circular motion of a charged particle in the presence of a uniform magnetic field.

                 r = \frac{mv}{qB}

Where: B is the strength magnetic field, q is the charge, v is its velocity and m is the mass of the particle.

From the question, B = 1.63 × 10^{-5}T, v = 121 m/s, Θ = 90^{0} (since it enters perpendicularly to the field), q = e  = 1.6 × 10^{-19}C and m = 9.11 × 10^{-31}Kg.

Thus,

         r = \frac{mv}{qB} ÷ sinΘ

But,  sinΘ =  sin 90^{0} = 1.

So that;

          r = \frac{mv}{qB}

            = (9.11 × 10^{-31} × 121) ÷ (1.6 × 10^{-19}  × 1.63 × 10^{-5})

            = 1.10231 × 10^{-28}   ÷ 2.608 × 10^{-24}

            = 4.2266 × 10^{-5}

            = 4.23 × 10^{-5} m

The radius 'r' of the electron's path is 4.23 × 10^{-5} m.

B. The frequency 'f' of the motion is called cyclotron frequency;

           f = \frac{qB}{2\pi m}

             =  (1.6 × 10^{-19}  × 1.63 × 10^{-5}) ÷ (2 ×\frac{22}{7} × 9.11 × 10^{-31})

             =  2.608 × 10^{-24} ÷  5.7263 × 10^{-30}

             = 455442.4323

          f  = 455.44 KHz

The frequency 'f' of the motion is 455.44 KHz.

3 0
3 years ago
Read 2 more answers
What does the diameter in meters need to be of a round parachute that the designer has determined needs to have an area of 500 s
Marrrta [24]
Area of a circle is
A= pi r^2
so
500m^2 = 3.14 r2
500/pi = r ^2
152.1549...=r^2
square root both sides
r=12.61566...
d=2r
d=25.2
to 3 sig fig
4 0
3 years ago
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