1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shtirl [24]
3 years ago
7

explain how average speed and average velocity are related to each other for an object in uniform motion

Physics
2 answers:
Tatiana [17]3 years ago
5 0

Explanation:

Average speed and average velocity both are different quantities.Speed is a scalar quantity but on the other hand velocity is a vector quantity.Speed deals with distance but on the other hand velocity deals with displacement and we know that displace is a vector quantity that is why velocity is a vector quantity.

Average\ speed\ =\dfrac{Total\ distance}{Total\ time}

Average\ velocity\ =\dfrac{Total\ displacement}{Total\ time}

If object is in uniform motion then speed and velocity will become same.

 

Alex787 [66]3 years ago
3 0
Both take the average speed.... however velocity also shows direction
You might be interested in
What is the weight of a 2.00-kilogram object on
Trava [24]
<span>(4) 19.6 N</span>
On Earth's surface, a mass of 1kg <span>exerts a force(weight) of 9.81 N
So the weight= 9.81x2.00
                      =19.62N
                      =19.6N</span>
3 0
3 years ago
Read 2 more answers
A laboratory electromagnet produces a magnetic field of magnitude 1.38 T. A proton moves through this field with a speed of 5.86
Vladimir [108]

.Answer;

Using Fmax=qVB

F=(1.6*10^-19 C)(5.860*10^6 m/s)(1.38 T)

ANS=1.29*10^-12 N

2. Using Amax=Fmax/ m

Amax =(1.29*10^-12 N) / (1.67*10^-27 kg)

ANS=1.93*10^15 m/s^2*

3. No, the acceleration wouldn't be the same. Since The magnitude of the electron is equal to that of the proton, but the direction would be in the opposite direction and also Since an electron has a smaller mass than a proton

3 0
3 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
Determine the MA based on the diagram below.
Len [333]

Answer:

d

Explanation:

4 0
2 years ago
Your friend of mass 50 kg can just barely float in fresh water.
gulaghasi [49]
The answer is 10 i think so 
7 0
3 years ago
Other questions:
  • What is radiation? What are the different types? ​
    15·2 answers
  • The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?
    15·2 answers
  • The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample
    5·1 answer
  • Ano ang pagkain a ng Bugtong sa Palaisipan?
    8·1 answer
  • That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.
    15·1 answer
  • Please help me guys never mind the calculations ​
    6·1 answer
  • . A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an
    11·1 answer
  • An airplane during departure has a constant acceleration of 3 m / s².
    15·1 answer
  • How does a mirage occur in a deser?explain with a labelled diagram.​
    15·2 answers
  • A bicyclist covers the first leg of a journey that is d1meters in t1seconds at a speed of v1m/s and the second leg of d2meters i
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!