<span>(4) 19.6 N</span>
On Earth's surface, a mass of 1kg <span>exerts a force(weight) of 9.81 N
So the weight= 9.81x2.00
=19.62N
=19.6N</span>
.Answer;
Using Fmax=qVB
F=(1.6*10^-19 C)(5.860*10^6 m/s)(1.38 T)
ANS=1.29*10^-12 N
2. Using Amax=Fmax/ m
Amax =(1.29*10^-12 N) / (1.67*10^-27 kg)
ANS=1.93*10^15 m/s^2*
3. No, the acceleration wouldn't be the same. Since The magnitude of the electron is equal to that of the proton, but the direction would be in the opposite direction and also Since an electron has a smaller mass than a proton
Answer:
On moon time period will become 2.45 times of the time period on earth
Explanation:
Time period of simple pendulum is equal to
....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth
As when we go to moon, acceleration due to gravity on moon is
times os acceleration due to gravity on earth
So time period of pendulum on moon is equal to
--------eqn 2
Dividing eqn 2 by eqn 1


So on moon time period will become 2.45 times of the time period on earth
The answer is 10 i think so