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3 years ago

explain how average speed and average velocity are related to each other for an object in uniform motion

Physics

2 answers:

Tatiana [17]3 years ago

5 0

Explanation:

Average speed and average velocity both are different quantities.Speed is a scalar quantity but on the other hand velocity is a vector quantity.Speed deals with distance but on the other hand velocity deals with displacement and we know that displace is a vector quantity that is why velocity is a vector quantity.

$Average\ speed\ =\dfrac{Total\ distance}{Total\ time}$

$Average\ velocity\ =\dfrac{Total\ displacement}{Total\ time}$

If object is in uniform motion then speed and velocity will become same.

Alex787 [66]3 years ago

3 0

Both take the average speed.... however velocity also shows direction

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Read 2 more answers

2 Points

Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

$:\implies$ Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

$:\implies$ 50 N = 10 kg × Acceleration

$:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}$

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3 years ago

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2 years ago

A commuter backs her car out of her garage with an acceleration of 1.40 m/s2.A) How long does it take her to reach a speed of 2.

AURORKA [14]

Answer:

(A) 1.43secs

(B) -2.50m/s^2

Explanation:

A commuter backs her car out of her garage with an acceleration of 1.40m/s^2

(A) When the speed is 2.00m/s then, the time can be calculated as follows

t= Vf-Vo/a

The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0

= 2.00-0/1.40

= 2.00/1.40

= 1.43secs

(B) The deceleration when the time is 0.800secs can be calculated as follows

a= Vf-Vo/t

= 0-2.00/0.800

= -2.00/0.800

= -2.50m/s^2

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2 years ago