c. Suppose we make the problem adversarial as follows: the two players take turns moving; a coin is flipped to determine the puz
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We have that the <em>temperature </em>at the <em>interface </em>of the two <em>layers</em>, in °F, and (b) the rate of heat transfer through the wall in Btu/h*ft^2 of surface area is given as
a)
b)
From the question we are told
A composite plane wall cons<em>i</em>sts of a 5-in.-thick layer of insulation (ks = 0.029 Btu/h*ft*°R) and a 0.75-in.-thick layer of siding (ks = 0.058 Btu/h*ft*°R).
The inner temperature of the insulation is 67°F. The outer temperature of the siding is -8°F.
<h3>Interface Temperature</h3>Generally the equation for the Terminal resistance is mathematically given as
b)
a)Interface Temp(T_i)
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The modulus of elasticity is 44.4GPa
E<u>xplanation:</u>
Given
original length L1=10cm
New length L2=10.036 cm
Force F=16000N
Stress of the bar σ=Force/Area
Change in length ΔL=L2-L1=10.036-10=0.036 cm
Strain is obtained by dividing the change in length by original length
Strain ε=ΔL/L1
=0.036/10=0.0036
Modulus of elasticity=stress/strain
=σ/ε
Pa