Answer:
![\mathbf{C_{10} = 137.611 \ kN}](https://tex.z-dn.net/?f=%5Cmathbf%7BC_%7B10%7D%20%3D%20137.611%20%5C%20kN%7D)
Explanation:
From the information given:
Life requirement = 40 kh = 40 ![40 \times 10^{3} \ h](https://tex.z-dn.net/?f=40%20%5Ctimes%2010%5E%7B3%7D%20%5C%20h)
Speed (N) = 520 rev/min
Reliability goal
= 0.9
Radial load
= 2600 lbf
To find C10 value by using the formula:
![C_{10}=F_D\times \pmatrix \dfrac{x_D}{x_o +(\theta-x_o) \bigg(In(\dfrac{1}{R_o}) \bigg)^{\dfrac{1}{b}}} \end {pmatrix} ^{^{^{\dfrac{1}{a}}](https://tex.z-dn.net/?f=C_%7B10%7D%3DF_D%5Ctimes%20%5Cpmatrix%20%5Cdfrac%7Bx_D%7D%7Bx_o%20%2B%28%5Ctheta-x_o%29%20%5Cbigg%28In%28%5Cdfrac%7B1%7D%7BR_o%7D%29%20%5Cbigg%29%5E%7B%5Cdfrac%7B1%7D%7Bb%7D%7D%7D%20%5Cend%20%7Bpmatrix%7D%20%5E%7B%5E%7B%5E%7B%5Cdfrac%7B1%7D%7Ba%7D%7D)
where;
![x_D = \text{bearing life in million revolution} \\ \\ x_D = \dfrac{60 \times L_h \times N}{10^6} \\ \\ x_D = \dfrac{60 \times 40 \times 10^3 \times 520}{10^6}\\ \\ x_D = 1248 \text{ million revolutions}](https://tex.z-dn.net/?f=x_D%20%3D%20%5Ctext%7Bbearing%20life%20in%20million%20revolution%7D%20%5C%5C%20%20%5C%5C%20x_D%20%3D%20%5Cdfrac%7B60%20%5Ctimes%20L_h%20%5Ctimes%20N%7D%7B10%5E6%7D%20%5C%5C%20%5C%5C%20x_D%20%3D%20%5Cdfrac%7B60%20%5Ctimes%2040%20%5Ctimes%2010%5E3%20%5Ctimes%20520%7D%7B10%5E6%7D%5C%5C%20%5C%5C%20x_D%20%3D%201248%20%5Ctext%7B%20million%20revolutions%7D)
![\text{The cyclindrical roller bearing (a)}= \dfrac{10}{3}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20cyclindrical%20roller%20bearing%20%28a%29%7D%3D%20%5Cdfrac%7B10%7D%7B3%7D)
The Weibull parameters include:
![x_o = 0.02](https://tex.z-dn.net/?f=x_o%20%3D%200.02)
![(\theta - x_o) = 4.439](https://tex.z-dn.net/?f=%28%5Ctheta%20-%20x_o%29%20%3D%204.439)
![b= 1.483](https://tex.z-dn.net/?f=b%3D%201.483)
∴
Using the above formula:
![C_{10}=1.4\times 2600 \times \pmatrix \dfrac{1248}{0.02+(4.439) \bigg(In(\dfrac{1}{0.9}) \bigg)^{\dfrac{1}{1.483}}} \end {pmatrix} ^{^{^{\dfrac{1}{\dfrac{10}{3}}}](https://tex.z-dn.net/?f=C_%7B10%7D%3D1.4%5Ctimes%202600%20%5Ctimes%20%5Cpmatrix%20%5Cdfrac%7B1248%7D%7B0.02%2B%284.439%29%20%5Cbigg%28In%28%5Cdfrac%7B1%7D%7B0.9%7D%29%20%5Cbigg%29%5E%7B%5Cdfrac%7B1%7D%7B1.483%7D%7D%7D%20%5Cend%20%7Bpmatrix%7D%20%5E%7B%5E%7B%5E%7B%5Cdfrac%7B1%7D%7B%5Cdfrac%7B10%7D%7B3%7D%7D%7D)
![C_{10}=3640 \times \pmatrix \dfrac{1248}{0.02+(4.439) \bigg(In(\dfrac{1}{0.9}) \bigg)^{\dfrac{1}{1.483}}} \end {pmatrix} ^{^{^{\dfrac{3}{10}}](https://tex.z-dn.net/?f=C_%7B10%7D%3D3640%20%5Ctimes%20%5Cpmatrix%20%5Cdfrac%7B1248%7D%7B0.02%2B%284.439%29%20%5Cbigg%28In%28%5Cdfrac%7B1%7D%7B0.9%7D%29%20%5Cbigg%29%5E%7B%5Cdfrac%7B1%7D%7B1.483%7D%7D%7D%20%5Cend%20%7Bpmatrix%7D%20%5E%7B%5E%7B%5E%7B%5Cdfrac%7B3%7D%7B10%7D%7D)
![C_{10} = 3640 \times \bigg[\dfrac{1248}{0.9933481582}\bigg]^{\dfrac{3}{10}}](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%203640%20%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1248%7D%7B0.9933481582%7D%5Cbigg%5D%5E%7B%5Cdfrac%7B3%7D%7B10%7D%7D)
![C_{10} = 30962.449 \ lbf](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%2030962.449%20%5C%20lbf)
Recall that:
1 kN = 225 lbf
∴
![C_{10} = \dfrac{30962.449}{225}](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%20%5Cdfrac%7B30962.449%7D%7B225%7D)
![\mathbf{C_{10} = 137.611 \ kN}](https://tex.z-dn.net/?f=%5Cmathbf%7BC_%7B10%7D%20%3D%20137.611%20%5C%20kN%7D)
Answer: a) The technology that deals with the generation, control and transmission of power using pressurized fluids
Explanation: Fluid power is defined as the fluids which are under pressure and then are used for generation,control and transmit the power. Fluid power systems produces high forces as well as power in small amount . These systems usually tend to have better life if maintained properly. The force that are applied on this system can be monitored by gauges as well as meter.
Answer:
The result in terms of the local Reynolds number ⇒ Re = [μ_∞ · x] / v
Explanation:
See below my full workings so you can compare the results with those obtained from the exact solution.
The answer is deindividuation - a psychological state in which a person does not feel individual responsibility.
Maybe it’s a vending machine, I’m confused too