Answer:
a) 8kW
b) $128
Explanation:
Given the coefficient of performance of the heat pump cycle to be 2.5
Energy delivered by the heat pump = 20kW
a) net power required to operate the heat pump = Energy delivered / coefficient of performance
Net power required = 20/2.5
= 8kW
b) Given the cost of electricity is $0.08 for 1kWhour
Since net power required to operate heat pump = 8kW
If the heat pump operate for 200hours, total power required for a month = 8kW×200hours = 1600kWhour
since 1kWh of electricity costs $0.08, cost of electricity used in a month when the pump operates for 200hour will be 1600kWh×$0.08 which is equivalent to $128
Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to ![\pi](https://tex.z-dn.net/?f=%5Cpi)
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem
a) For the thermal efficiency we have
![\eta_{th} = \frac{Q_{out}}{Q_{in}} = \frac{|W|}{|Q_h|}\\\eta_{th} = \frac{|W|}{|W|+|Q_2|}](https://tex.z-dn.net/?f=%5Ceta_%7Bth%7D%20%3D%20%5Cfrac%7BQ_%7Bout%7D%7D%7BQ_%7Bin%7D%7D%20%3D%20%5Cfrac%7B%7CW%7C%7D%7B%7CQ_h%7C%7D%5C%5C%5Ceta_%7Bth%7D%20%3D%20%5Cfrac%7B%7CW%7C%7D%7B%7CW%7C%2B%7CQ_2%7C%7D)
With the previously values we know that
and
(convert the min to sec)
Replacing the values
![\eta_{th}=\frac{8}{8+1440/6}=\frac{1}{31}\\\eta_{th}\% = 3.225\%](https://tex.z-dn.net/?f=%5Ceta_%7Bth%7D%3D%5Cfrac%7B8%7D%7B8%2B1440%2F6%7D%3D%5Cfrac%7B1%7D%7B31%7D%5C%5C%5Ceta_%7Bth%7D%5C%25%20%3D%203.225%5C%25)
b) We use the formula of carnot efficiency
![\eta_{th}=1-\frac{T_l}{T_h}\\\eta_{th}\% =(1-\frac{280}{295})*100\\\eta_{th}\%=5.085\%](https://tex.z-dn.net/?f=%5Ceta_%7Bth%7D%3D1-%5Cfrac%7BT_l%7D%7BT_h%7D%5C%5C%5Ceta_%7Bth%7D%5C%25%20%3D%281-%5Cfrac%7B280%7D%7B295%7D%29%2A100%5C%5C%5Ceta_%7Bth%7D%5C%25%3D5.085%5C%25)
**Note that apply the formula of carnot cycle we need to consider that there is no exchange of heat, there is no friction and the reservior are completely insulated
I believe he should use two separate plants. One just for tracking the growth with plain water and the other for sugar.
Really tall they we one of the tallest buildings in New York