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Answer:
rate of heat transfer = 9085708.80 W
Explanation:
Given:
Inside diameter, D = 5.1 cm
= 5.1 x m
Average velocity, V = 7 m/s
Mean temperature, T = (66+38) /2
= 52°C
Therefore kinematic viscosity at 52°C is ν = 0.104 X
/ s
Prandtl no., Pr = 0.021
We know Renold No. is
Re =
Re =
= 3.432 X
Therefore the flow is turbulent.
Since the flow is turbulent and the ratio of L/D is greater than 60 we can use Dittua-Boelter equation.
Nu = 0.023 .
= 0.023 x x
= 1221.52
Since Nu =
h =
=
= 225143.3
Therefore rate of heat transfer, q = h.A(T-
q= 225143.3 x 2πrh ( 66-38)
= 225143.3 X 2π X
= 9085708.80 W