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erica [24]
2 years ago
7

What is the pOH of a solution with [OH^ - ]=1.4*10^ -13

Chemistry
1 answer:
Dimas [21]2 years ago
6 0

Answer:

12.9

Explanation:

From the question given, the concentration of the hydroxide ion is given:

[OH^-] = 1.4 x 10^ -13M

pOH =?

pOH = —Log [OH^-]

pOH = —Log 1.4 x 10^ -13

pOH = 12.9

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Valeric acid, HC5H9O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of magnesium valerate, a nerve-calming agent. What is the hy
Studentka2010 [4]

Answer:

[H^+]=0.00332M

Explanation:

Hello,

In this case, considering the dissociation of valeric acid as:

HC_5H_9O_2 \rightleftharpoons C_5H_9O_2 ^-+H^+

Its corresponding law of mass action is:

Ka=\frac{[H^+][C_5H_9O_2^-]}{[HC_5H_9O_2]}

Now, by means of the change x due to dissociation, it becomes:

Ka=\frac{(x)(x)}{0.737-x}=1.5x10^{-5}

Solving for x we obtain:

x=0.00332M

Thus, since the concentration of hydronium equals x, the answer is:

[H^+]=x=0.00332M

Best regards.

7 0
3 years ago
Question 2(Multiple Choice Worth 3 points) What happens to the rate of most reactions as the reaction progresses? The rate remai
Sav [38]

Answer: -

The rate decreases as the concentration of the reactants decreases

Explanation: -

A reaction involves change of the reactants into products.

Initially there is only reactants. So the rate if reaction is high.

After some time there are products. So the amount of reactant is less.

Reactions involve collisions of reactant molecules. As the reactant amount decreases, collisions between the reactants decreases. As such the rate of reaction decreases with the progress of the reaction.

3 0
2 years ago
Answer soon please ​
erica [24]

Answer:

The sphere on the left as it has more mass.

Explanation:

Inertia is the resistance to changes of motion.

5 0
3 years ago
HELPPPP PLEASEE!!!!!!!
OlgaM077 [116]

I think the answer is yes

3 0
2 years ago
Read 2 more answers
What is 190 K in degrees Celsius? Show your work for full credit.
saveliy_v [14]

Answer:

-83.15

Explanation:

190K − 273.15 = -83.15°C

3 0
2 years ago
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