What is extremely lightweight and exists in a cloud orbiting the nucleus
2 answers:
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We have to solve this question using the stoichiometry of the reaction:
The equation of the reaction is;
According to the question;
Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles
From the stoichiometry of the reaction:
Since;
24 moles of CO2 released 15,026 KJ
0.48 moles of CO2 will release 0.48 * 15,026/24
= 301 KJ of heat.
Answer:
Value = 1.80 g/cm³ (Approx)
Explanation:
Given:
Computation:
Value = 1.80 g/cm³ (Approx)