Answer:
2Fe + O₂ -------------------> 2FeO
8 mol Fe produce
8 mol Fe * 2 mol FeO / 2 mol Fe = 8 mol FeO
Mass of FeO = 8 mol FeO * 71.85 g/mol = 574.8 grams FeO
Explanation:
Having 8 mol of Iron means 8 moles of iron oxide can be produced. Each mole of iron oxide has a molecular weight of 71.85 grams. Therefore, 8 moles of iron oxide should weight 574.8 grams.
Answer is: <span>B) June 21.
This is summer solstice or midsummer.
</span>Summer solstice occurs when a planet's geographical pole<span> on Northern H</span>emisphere is most inclined toward the Sun. <span>Earth's maximum </span>axial tilt<span> toward the </span>Sun is 23.44° and <span>the Sun reaches its </span>highest altitude<span> of the year on the summer </span><span>solstice.</span>
Answer:
p1/T1=p2/T2
760mmHg/212°F=731mmHg/T2
T2= 203.91°F
760mmHg/100°C=731mmHg/T2
T2= 96.18°C
Explanation:
You'd have to choose in which units you want to express the temperature.
I do hope that no person does this.
Answer:
- 50.7 kJ.
Explanation:
- To get the enthalpy change for the reaction:
Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).
- We must orient the given reactions in a way that its sum give the required reaction.
The first reaction be as it is:
Mn₃O₄(s) + 4CO(g) ⟶ 3Mn(s) + 4CO₂(g), <em>ΔH₁ = 255.6 kJ.</em>
The second reaction should be reversed and multiplied by 3 and also the value of its ΔH must multiplied by (- 3):
3Mn(s) + 3CO₂(g) ⟶ 3MnO(s) + 3CO(g), <em>ΔH₂ = (- 3)(102.1 kJ) = - 306.3 kJ.</em>
- By summing the two reactions after the modification, we get the required reaction:
<em>Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).</em>
<em></em>
<em>∴ ΔH rxn = ΔH₁ + ΔH₂ = (255.6 kJ) + (- 306.3 kJ) = - 50.7 kJ.</em>
