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Alexxx [7]
4 years ago
8

What is the IMA of the lever pictured? 0.18 0.20 0.90 5

Chemistry
2 answers:
bekas [8.4K]4 years ago
8 0
1/5 would be your answer.
IceJOKER [234]4 years ago
6 0
<span>The ideal mechanical advantage represents the number of times the input force is multiplied under ideal conditions, that is with no friction. Actual mechanical advantage on the other hand stands for the number of times the input force is multiplied. 
Hence; IMA (ideal mechanical advantage)=Le/Lr
The Lr =0.3 +1.2 = 1.5 and Le= 0.3
       = 0.3/1.5 = 1/5;
therefore the correct answer is 0.2</span>
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Na3po4 dissolves in water to produce an electrolytic solution. what is the osmolarity of a 2. 0 × 10-3 m na3po4 solution?
vichka [17]

When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.

Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.

In other words osmolarity is the multiple if molarity

Osmolarity = i× molarity

Here i represents the van't Hoff factor,

Na_{3}PO_{4} ⇒ 3Na^{+} + PO_{4} ^{-}

3  Moles of Na_{} ^{+} + 1 mole PO_{4} ^{-} = 4

The number of moles of particles of solute produced in solution are actually called osmoles.

As a result, the van't Hoff factor will be equal to

i=4 Moles ions produced (osmoles) 1mole Na_{3} PO_{4} .dissolved =4

Since we know that,

Na_{3} PO_{4} = 2.0 * 10^{-3} M

Osmolarity =

4*2.0*10^{-3} M = 8.0 * 10^{-3}  osmol L -10s

Thus, the Osmolarity of given solution is 0.008 osmol/L.

learn more about Osmolarity:

brainly.com/question/13597129

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6 0
2 years ago
Calculate the molarity of an aqueous solution of NaOH if its pH is measured and found to be 12.00.
alisha [4.7K]

Answer:

Explanation:

pH = 12

[H⁺] = 10⁻¹²

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[OH⁻¹ ] = 10⁻²

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NaOH is a strong base so it dissociates 100%

[OH⁻¹ ] = 10⁻²

molarity of NaOH = 10⁻² M

= .01 M .

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Egg molecules will never undergo these reactions without the input of energy (usually in the form of heat)

I hope this helps, if not, let me know :)

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