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3 years ago

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5. In which group of elements do most atoms have completely filled s and p velence sublevels? A) halogens B) noble gases C) alka

li mctals D) alkaline earth metals

1 answer:

ivanzaharov [21]3 years ago

4 0

Noble Gases is the answer (please give me brainliest

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago

Why was Becquerel’s experiment a first step in discovering radioactivity?

galina1969 [7]

This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.

5 0

3 years ago

Read 2 more answers

During respiration, a plant uses glucose (sugar) and oxygen to give it the energy it needs to survive. During this process _____

garri49 [273]

Water and carbon dioxide .

6 0

3 years ago

How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

nalin [4]

Answer:

V₁ = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁ = 0.10 M×300.0 mL

3.0 M ×V₁ = 30 M.mL

V₁ = 30 M.mL /3.0 M

V₁ = 10 mL

3 0

3 years ago

Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 783.5-g sam

anastassius [24]

First, is to solve the molar mass of the herbicide, with a formula
<span>C3H8NO5P
C3 = 12 ( 3 ) = 36
H8 = 1 ( 8 ) = 8
N = 14
O5 = 16 ( 5 ) = 80
P = 31
so in total the molar mass of </span><span>C3H8NO5P is 36 + 8 + 14 + 80 + 31 = 169 g/mol

number of moles = 783.5 g ( 1 mol / 169 g)
number of moles = 4.64 mol </span><span>C3H8NO5P</span>

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3 years ago