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Veseljchak [2.6K]
3 years ago
15

All radioactive nuclides undergo what

Chemistry
1 answer:
kotykmax [81]3 years ago
6 0
They undergo nuclear fission.
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How is humility related to air pressure
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Humid air has higher pressure because of the heaviness of water humid air is lighter so it has lower pressure.
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9. Which of Earth’s sphere consists of all living things? A. hydrosphere B. geosphere C. biosphere
Anna007 [38]

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i think its b

Explanation:

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3 years ago
Read the following summary, which describes a body process. Then, answer the question.
Maksim231197 [3]

Answer:

Respiritation

Explanation:

Its Respiration because the process of breathing is known as respiration and also read the paragraph hhhhhhhhhhhhhhhhhhhhhhhh

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Under a certain set of conditions, the percent yield of a reaction that produces carbon dioxide is 75.0%. What mass in grams of
ExtremeBDS [4]

Answer:

Actual yield = 20.03g

Explanation:

% yield = 100.\frac{actual yield}{theoretical yield}% yield = 100. \frac{actual \ yield}{theoretical \ yield}

Actual yield = % yield.(theoretical yield) / 100

Actual yield = 75.26.7/100

Actual yield = 20.025

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3 years ago
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A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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