All radioactive nuclides undergo what

Find the number of moles in 6120 ions of NaCl . Round your answer to two decimal places. Input your answer as 1.03E23, which is

FrozenT [24]

Answer:

Explanation:

NaCl = Na⁺ + Cl⁻

6120 ions of NaCl will contain 3060 ions of Na⁺ and 3060 ions of Cl⁻ , forming 3060 molecules of NaCl .

6.02 x 10²³ molecules of NaCl = 1 mole

3060 molecules of NaCl = 3060 x 10⁻²³ / 6.02 moles

= 508.30 x 10⁻²³ moles

= 5.08 x 10⁻²¹ moles

Answer : 5.08E-21 moles .

5 0

2 years ago

What happens when oppositely charged ions get close together?

kirill [66]

Answer:

They attract each other

4 0

2 years ago

Read 2 more answers

Explain how atoms organize to create larger structures?

Mrrafil [7]

Answer:

First of all they are super tiny particles of neutrons, electrons and protons. Then they come together to organize a structure of atom. Atoms come together to form a molecule and smaller molecules work together to form macromolecules. Thus, how they organize and form building blocks of a substance.

Hope it helps!<3

6 0

2 years ago

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

2 years ago

Chapter 2.4.1. The ______ energy lost by the inward movement of nickel-iron within a differentiating molten planetary body would

Gwar [14]

Answer:b. gravitational, kinetic, thermal

Explanation:

The above explains the mechanism of the core forming process on earth/planet.

It is believed that this process might has contributed significantly to a planet's early stages heating. The time when these core-forming event happened is thought to have been mainly completed very early when Earth was young . The type of this event rather than it being seen as a single catastrophic event, it is likely to have been as a result of contractions on the earth severally.

The addition of partially differentiated material from another giant impact the rate of this spasm , and it increases each time the planet's mass is to increased.

This is a little on the history of planetary evolution.

8 0

3 years ago