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Veseljchak [2.6K]
3 years ago
15

All radioactive nuclides undergo what

Chemistry
1 answer:
kotykmax [81]3 years ago
6 0
They undergo nuclear fission.
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Hydrogen bonding among water molecules gives water all of the following important properties, except: strong cohesion among the
motikmotik

Answer:

Answer here is A: Transparent colour."

Explanation:

Hydrogen bonds here in water provides a lot of benefits which includes cohesion, releasing heat when forming, Also because of the fact that water molecules are polar, they form hydrogen molecules and give water some characteristics which ranges from high boiling point, relative gravity, adhesion ad also cohesion. It is also known that oxygen atom attracts the electrons more strongly than the hydrogen.

    A transparent colour falls in no place and do not really have any correlation in oxygen and hydrogen relationship.

5 0
4 years ago
Determine the number of electrons transferred in the balanced chemical equation. h2o
melomori [17]
I think the answer to this question is three or 3
5 0
3 years ago
How much energy in joules, does it take to heat a 55 gram sample of ice from-10°C to
Lostsunrise [7]

Energy needed : Q = 1105.5 J

<h3>Further explanation</h3>

Given

mass = 55 g

Temperature from -10°C to 0°C

Required

Energy

Solution

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Input the value :

Q = 55 g x 2.01 J/g ° C  x (0-(-10))

Q = 1105.5 J

4 0
4 years ago
What structural units make up network solids
zheka24 [161]
Nonmetal Atom is the answer.
5 0
3 years ago
A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem
Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat gained  = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = 0.0923cal/g^oC      

\Delta T=\text{Change in temperature} 

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC

Now put all the given values in the above formula, we get the final temperature of copper.

299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)

T_{final}=87.29^oC

Therefore, the final temperature of the copper is, 87.29^oC

4 0
4 years ago
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