2Ag +(aq) + SO4 2-(aq)----->Ag2SO4 (s)
Answer:
Third Law of motion. (answer C)
Explanation:
This is an example of Newton's Third Law of motion which normally translates into Action/Reaction. That is : the expelled air exerts a force in the direction opposite to that of the motion of the air that goes out. It is the same as propulsion in a rocket.
Answer:
The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).
Explanation:
The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
