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Elena-2011 [213]
3 years ago
8

Which two forces keep the planets and moons in their orbits?

Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
6 0
It is gravity and intrtia
jeyben [28]3 years ago
5 0

Answer:

“Without gravity, the planets' inertia would keep them moving in straight lines. Gravity “steers” the planets in their oval paths around the Sun. Together, gravity and inertia keep the planets in their orbits.”

Explanation:

BRAINLIEST PLZZZ

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Ch3cooh (acetic acid) can form hydrogen bonds between its molecules. based on the lewis structure shown below, how many hydrogen
never [62]
Answer:
           Number of Hydrogen Bond Acceptor atoms  =  2

           Number of Hydrogen Bond Donor atoms  =  1

Explanation:
                   Hydrogen bond interactions are formed between those molecules which contains partial positive hydrogen atoms bonded covalently to most electronegative atoms like Oxygen, Nitrogen and Fluorine. 
                   When hydrogen is attached to Oxygen, Nitrogen or Fluorine its electron density decreases and gets partial positive charge, this partial positive charged hydrogen atom then makes hydrogen bonding with the most electronegative element (partial negative) of neighbor molecule.
                    In Acetic acid there are two oxygen atoms hence there are two most electronegative elements therefore, two Hydrogen Bond Acceptor atom and each oxygen atom can accept two hydrogen bonds.
                    Also, it contains only one Hydrogen atom attached to oxygen atom so it has one Hydrogen Bond Donor atom.

4 0
3 years ago
What happens when Mg forms an ionic bond?
uysha [10]

Answer:

option 1st is correct gains 1 electron and becomes a-1.

4 0
3 years ago
A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
2 years ago
What is neutralisation reaction?<br>​
valina [46]

Answer:

In chemistry, neutralization or neutralisation (see spelling differences) is a chemical reaction in which acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.

6 0
3 years ago
Read 2 more answers
A student measures 10 g of baking soda and mixes it with 5 grams of vinegar. The mixture begins to bubble and fizz and feels col
Tomtit [17]

Answer:

Some of the product is a gas that goes to the atmosphere.

Explanation:

Based on the chemical reaction of baking soda (Sodium bicarbonate: NaHCO₃) with vinegar (Acetic acid: CH₃COOH):

NaHCO₃(aq) + CH₃COOH(aq) → H₂O(aq) +  CO₂(g) + CH₃COONa(aq)

When the reaction occurs, one of the products (CO₂) is a gas that will disappear of the mixture to stay in the atmosphere. That is the reason why there are missing 3 grams.

5 0
2 years ago
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