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kolezko [41]
2 years ago
7

34. Which statement describes what occurs in the

Chemistry
1 answer:
Rudik [331]2 years ago
5 0

Answer:

3 Both mass and charge are conserved.

Explanation:

The equation of the reaction is;

Cu(s) + 2Ag+ (aq) → Cu2+ (aq)  + 2Ag(s)

A redox reaction is an acronym for oxidation-reduction reaction. This refers to a reaction in which the oxidation number of one specie is increased while the oxidation number of the other specie is decreased.

This means that one specie looses electrons while the other specie gains electrons. Here, Cu(s) looses electrons while Ag+(aq) gains electrons from left to right in the reaction.

In a redox reaction, both mass and charge are conserved. This means that the total mass and charge on the reactants side is the same as the total mass and charge on the products side.

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How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?
devlian [24]

<u>Answer:</u> The amount of energy required to raise the given amount of temperature is 6400 J

<u>Explanation:</u>

To calculate the heat absorbed by the lead, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

\Delta T = change in temperature = 250°C

Putting values in above equation, we get:

q=200g\times 0.128J/g^oC\times 250^oC=6400J

Hence, the amount of energy required to raise the given amount of temperature is 6400 J

4 0
3 years ago
predict where an unknown element that has these properties could fit in the periodic table 62 protons and electrons
Vesnalui [34]
Position of element in periodic table is depend on the electronic configuration of element.

Element with 62 electrons has following electronic configuration:
<span>1s2 2s2 </span>2p6 <span>3s2 </span>3p6 4s2 3d10 4p6 <span>5s2 </span>4d10 5p6 4f6 <span>6s<span>2
</span></span>
From above electronic configuration, it can be seen that highest value of principal quantum number, where electron is present, is 6. Hence, element belongs to 6th period.

Further, last electron has entered f-orbital, hence it is a f-block element. Position of f-block element is the bottom of periodic table.

Further, there are 6 electrons in f-orbital. Hence, it is the 6th f-block element in 6th period of periodic table. 
5 0
3 years ago
UHHH helpppp maya cause uh she d.a.n.g d.u.m.b.
inna [77]

Answer:

17

Explanation:

the mass number of the element which is protons and neutrons is 17+18=35

electronic configuration is 2, 8, 7

valency of the element is 1 therefore the atomic number is 17

6 0
2 years ago
Read 2 more answers
In the reaction 2co ( g) + o2( g) → 2co2( g), what is the ratio of moles of oxygen used to moles of co2produced?
KIM [24]
In the reaction 2co ( g) + o2( g) → 2co2( g), the ratio of moles of oxygen used to moles of co2produced is 1:2.
8 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
3 years ago
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