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erik [133]
3 years ago
9

Solve 10q + 15n = 49 for 'q'. show steps please

Mathematics
1 answer:
klasskru [66]3 years ago
3 0
\displaystyle 10q + 15n=49\quad \Big|-15n\\\\10q=49-15n\quad \Big|:10\\\\q= \frac{49-15n}{10}
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(3x – 70) (3y+40) 120 x
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3x-70

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(3y+40 ) 120x is the answer of that question answer

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dimulka [17.4K]

Answer:

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Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

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Z = \frac{X - \mu}{\sigma}

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In this problem, we have that:

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This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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3 years ago
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Complete Question

The complete question is on the first uploaded image

Answer:

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Step-by-step explanation:

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