Answer:
v = 1130 cm³
Explanation:
Given data:
Volume of sample = ?
Mass of Al sample = 3.057 Kg (3.057 Kg× 1000g/1 Kg = 3057g)
Density of Al sample = 2.70 g/cm³
Solution:
Formula:
d = m/v
d = density
m = mass
v= volume
by putting values
2.70 g/cm³ = 3057g /v
v = 3057g /2.70 g/cm³
v = 1130 cm³
Answer: 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.
Justification:
Althought the question is too open, other answers may arise, the most remarkable similarity between the two compounds is that both are diatomic.
That means that both molecules oxygen, O₂, and carbon monoxide, CO have two atoms.
So, 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.
You must remember that 1 mol means a specific number. It is Avogadro's number, which is 6.022 × 10 ²³.
So 1 mol of CO and 1 mol of O₂ are the same number of representative particles: 6.022 ×10²³ molecules eac, and two times that number of atoms each (since each molecule has two atoms).
<span>The balloons volume as it
rises increases because at higher altitude external pressure is lower, so the
air molecules inside the balloons tends to expand more to attain mechanical
equilibrium, where the external pressure and internal pressure are equal. Unlike
when the balloon is on the ground, external pressure is great so the gas
molecule cannot push the walls of the balloon so it is like underinflated.</span>
C I think not sure give it a try
Answer:
[H₂SO₄] = 0.255M
Explanation:
H₂SO₄ + 2KOH => K₂SO₄ + 2H₂O
2(M x V)acid = (M x V)base => M(acid) = (M x V)base /2·Vacid
[H₂SO₄] = (0.5M)(25.5ml)/2(25.0ml) = 0.255M
