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Ede4ka [16]
2 years ago
13

How many grams of h2o are needed to produce 45g of NO

Chemistry
1 answer:
schepotkina [342]2 years ago
4 0

We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.
Explanation:
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
→
N
H
3
(
g
)
11.27

g
of ammonia represents
11.27
⋅
g
17.03
⋅
g
⋅
m
o
l
−
1

=

?
?

m
o
l
.
Whatever this molar quantity is, it is clear from the stoichiometry of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?
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Mariana [72]
The volume of the gas will be decreased. Answer lies on the understanding of kinetic energy of particles and how particles occupy certain amount of space.
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3 0
3 years ago
For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?
jekas [21]
In this question given concerning the atom's electron, the number of energy sublevels present in the principal energy level n = 4 is to be determined. For this matter, it should be remembered that the number of sublevels of a certain principal energy level is equal to n. For this item, the number of sublevels is also 4. That is s, p, d and f.
6 0
3 years ago
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Ionic bonds Select one: a. result from sharing electrons. b. result from transferring electrons. c. result from like charge attr
Naddika [18.5K]
<h2>Ionic bonds result from transferring of electrons</h2>

Explanation:

  • Ionic bonds result from transferring of electrons.
  • An ionic bond is also referred to as an electrovalent bond.
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2 years ago
10 To draw a perfect circle, you'll need: A A protractor B. A sextant С A compass D A spirograph 10 of 10​
mestny [16]

Answer:

B

Explanation:

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7 0
3 years ago
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prohojiy [21]

The volume of O₂ : 21 L

<h3>Further explanation</h3>

Given

8.7 grams of C₂H₄

Required

Volume O₂

Solution

Reaction

C₂H₄ + 3 O₂ ⇒ 2 CO₂ + 2 H₂O

mol C₂H₄(MW= 28 g/mol) :

= mass : MW

= 8.7 g : 28 g/mol

= 0.311

From the equation, mol  O₂ :

= 3/1 x mol C₂H₄

= 3/1 x 0.311

= 0.933

At STP, 1 mol gas=22.4 L, so for 0.933 mol :

= 0.933 x 22.4 L

= 20.899 L ≈ 21 L

6 0
2 years ago
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