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2 years ago

How many grams of h2o are needed to produce 45g of NO

1 answer:

4 0

We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.
Explanation:
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
→
N
H
3
(
g
)
11.27

g
of ammonia represents
11.27
⋅
g
17.03
⋅
g
⋅
m
o
l
−
1

=

?
?

m
o
l
.
Whatever this molar quantity is, it is clear from the stoichiometry of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?

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Is using gasoline to drive a chemical or physical

Flauer [41]

Answer:

Explanation:

Driving a car (burning gas is a chemical change) and almost all the plastics we use are made by chemical reactions of different components.

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2 years ago

In the laboratory you dilute 5.32 mL of a concentrated 6.00 M perchloric acid solution to a total volume of 100 mL. What is the

8_murik_8 [283]

Answer:

0.3192 M

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5.32 mL Molarity of stock solution (M1) = 6 M

Volume of diluted solution (V2) = 100 mL

Molarity of diluted solution (M2) =?

We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:

M1V1 = M2V2

6 × 5.32 = M2 ×100

31.92 = M2 × 100

Divide both side by 100

M2 = 31.92 / 100

M2 = 0.3192 M

Therefore, the molarity of the diluted solution is 0.3192 M.

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2 years ago

The ksp of pbbr2 is 6.60× 10–6. what is the molar solubility of pbbr2 in 0.500 m kbr solution

Alex_Xolod [135]

The solubility of PbBr₂(s) with the presence of 0.500 M of KBr is 2.64 x 10⁻⁵ M.

4 0

3 years ago

Read 2 more answers

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th

oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , $n=\dfrac{2.666}{16}=0.167\ mole$ .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , $m=12\times 0.167=2\ g$ .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

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2 years ago

True or false transuranium elements are synthetic elements with atomic #’s of 93 or higher.

devlian [24]

It's absolutely TRUE...........

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3 years ago