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Furkat [3]
3 years ago
15

5. Some areas of the nation have limestone in the soil and lake bottoms. Explain how the presence of this mineral acts as a natu

ral buffer against acid rain.
Chemistry
1 answer:
mixer [17]3 years ago
3 0

Limestone is calcium carbonate Ca(Co3) it's dissociation equation is as follows: Ca(CO3) <----> Ca+2 + CO3-2 

but the solubility is very small in the presence of acid by LeChatlier's Principle you can shift to the right by adding acid 

H+ + CO3-2 <-----> H+CO3- (the bicarbonate ion which is really soluble) 

The system will pull more and more limestone out into solution as acid is added and neutralize the acid coming from the rain.

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What the common uses for Bohrium?
lora16 [44]

Answer:

Explanation:

Bohrium's most stable isotope, bohrium-270, has a half-life of about 1 minute. It decays into dubnium-266 through alpha decay. Since only a few atoms of bohrium have ever been made, there are currently no uses for bohrium outside of basic scientific research.

5 0
3 years ago
Read 2 more answers
Rusty is a forensic investigator examining the crime scene of a homicide. The medical examiner has determined that the victim di
boyakko [2]

Answer:

The presence of dust on the victim's right or left hand

Explanation:

The presence of powder, the route of the bullet, and the damage the bullet generates tells us what the caliber of the weapon was like, and type.

The presence of gunpowder in the hand is a consequence of the person being shot, usually in the victim's skilled hand.

4 0
3 years ago
A solution was prepared by dissolving 195.0 g of KCl in 215 g of water. Calculate the mole fraction of KCl. (The formula weight
defon

Answer:

Approximately 0.180.

Explanation:

The mole fraction of a compound in a solution is:

\displaystyle \frac{\text{Number of moles of compound in question}}{\text{Number of moles of all particles in the solution}}.

In this question, the mole fraction of \rm KCl in this solution would be:

\displaystyle X_\mathrm{KCl} = \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}.

This solution consist of only \rm KCl and water (i.e., \rm H_2O.) Hence:

\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})}\end{aligned}.

From the question:

  • Mass of \rm KCl: m(\mathrm{KCl}) = 195.0\; \rm g.
  • Molar mass of \rm KCl: M(\mathrm{KCl}) = 74.6\; \rm g \cdot mol^{-1}.
  • Mass of \rm H_2O: m(\mathrm{H_2O}) = 215\; \rm g.
  • Molar mass of \rm H_2O: M(\mathrm{H_2O}) = 18.0\; \rm g\cdot mol^{-1}.

Apply the formula \displaystyle n = \frac{m}{M} to find the number of moles of \rm KCl and \rm H_2O in this solution.

\begin{aligned}n(\mathrm{KCl}) &= \frac{m(\mathrm{KCl})}{M(\mathrm{KCl})} \\ &= \frac{195.0\; \rm g}{74.6\; \rm g \cdot mol^{-1}} \approx 2.61\; \em \rm mol\end{aligned}.

\begin{aligned}n(\mathrm{H_2O}) &= \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \\ &= \frac{215\; \rm g}{18.0\; \rm g \cdot mol^{-1}} \approx 11.9\; \em \rm mol\end{aligned}.

The molar fraction of \rm KCl in this solution would be:

\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})} \\ &\approx \frac{2.61 \; \rm mol}{2.61\; \rm mol + 11.9\; \rm mol} \approx 0.180\end{aligned}.

(Rounded to three significant figures.)

8 0
3 years ago
What has the highest ionization energy?
Inessa [10]
<span>the highest ionization energy is Be, it is higher and righter than other elements in periodic table, so it harder to remove electron from its atom</span>
5 0
3 years ago
HClO4 acid solution has a concentration of 5 Molarity. Calculate the concentration of this solution in
Nutka1998 [239]

Answer:

1. Percentage by weight = 0.5023 = 50.23 %

2. molar fraction =0.153

Explanation:

We know that

Molar mass of HClO4 = 100.46 g/mol

So the mass of 5 Moles= 5 x 100.46

       Mass (m)= 5 x 100.46 = 502.3 g

Lets assume that aqueous solution of HClO4  and the density of solution is equal to density of water.

Given that concentration HClO4 is 5 M it means that it have 5 moles of HClO4 in 1000 ml.

We know that

Mass = density x volume

Mass of 1000 ml  solution = 1 x 1000 =1000     ( density = 1 gm/ml)

            m'=1000 g

1.

Percentage by weight = 502.3 /1000

Percentage by weight = 0.5023 = 50.23 %

2.

We know that

molar mass of water = 18 g/mol

mass of water in 1000 ml = 1000 - 502.3 g=497.9 g

So moles of water = 497.7 /18 mole

moles of water = 27.65 moles

So molar fraction = 5/(5+27.65)

molar fraction =0.153

6 0
3 years ago
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