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4 years ago

A vehicle that goes from 5m/s to 45m/s in 8s. what is its acceleration?

Physics

1 answer:

GaryK [48]4 years ago

3 0

Answer: 5m/s^2

Explanation:

V= 45m/s

U = 5m/s

t = 8s

a =?

V = u + at

45 = 5 + 8a

8a = 45 — 5

8a = 40

a = 40 / 8

a = 5m/s^2

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Answer:

Explanation:

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3 years ago

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vladimir1956 [14]

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4 years ago

What is imperceptible human motion?

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4 years ago

3. When a magnetic sector instrument was operated with an accelerating voltage of 4.50*103 V, a field of 0.251 T was required to

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Answer:

The answer is " $4,500 - 225 \ V$ ".

Explanation:

Using formula for calculating the Voltage:

$M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\$

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