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3 years ago

A vehicle that goes from 5m/s to 45m/s in 8s. what is its acceleration?

Physics

1 answer:

GaryK [48]3 years ago

3 0

Answer: 5m/s^2

Explanation:

V= 45m/s

U = 5m/s

t = 8s

a =?

V = u + at

45 = 5 + 8a

8a = 45 — 5

8a = 40

a = 40 / 8

a = 5m/s^2

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In the reaction C6H12 + ________ O2----> 6H20 + 6CO2, what coefficient should be placed in front of 02 to balance the reactio

Alborosie

All you need to do is count the number of Oxygen the Products:
In 6H2O, you have 6 oxygen, and in 6CO2, you have 6 Dioxygen so 12 Oxygen. So a total of 12 + 6 = 18 atoms of Oxygen, or 9 atoms of dioxygen.
So the coefficient that should be placed in front of O2 to balance the reaction is 9:
C6H12 + 9O2 ---> 6H2O + 6CO2

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7 0

3 years ago

Read 2 more answers

An object that is accelerating may be

Elenna [48]

It must be either speeding up, or slowing down, or turning. There are no other possibilities.

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2 years ago

A ball is thrown straight up from the ground with an unknown velocity. It reaches its highest point after 5.5 s. With what veloc

Maslowich

V = u + at
0 = u -9.8 x 5.5
u = 9.8 x 5.5 = 53.9 m/s

5 0

3 years ago

Pascal in term fundamental unit is?

Aleksandr-060686 [28]

Answer: SI unit of pressure

Explanation: The pascal (pronounced pass-KAL and abbreviated Pa) is the unit of pressure or stress in the International System of Units (SI). Reduced to base units in SI, one pascal is one kilogram per meter per second squared; that is, 1 Pa = 1 kg · m-1 · s-2.

Hope this helps! Have a fantastic rest of ur day, luv!

8 0

3 years ago

A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the

sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

$x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg$

Since the frictional force $f_k$ is equal to $f_k=\mu_k N=\mu_k mg$ , then we have that the acceleration is:

$a=\frac{\mu_k mg}{m}=\mu_k g$

Now, from the definition of acceleration we get:

$a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}$

And, as the final velocity is zero because the box gets to a stop, we have:

$t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}$

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

$t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s$

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

$v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}$

Finally, we calculate the displacement:

$x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm$

This means that the box moves 7.29cm backwards relative to the belt.

4 0

2 years ago