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RideAnS [48]
3 years ago
9

A theory was not originally a hypothesis. true or false?

Physics
1 answer:
Serhud [2]3 years ago
8 0
False.

Theories are hypotheses that have been shown to accurately and predictably explain results obtained through repeated experimentation, to the point where the hypothesis can be assumed to be true. Then, such a hypothesis would be considered a theory.
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A roller coaster is stationary at the top of a ramp.
Serjik [45]

Answer:

A

Explanation:

The roller coaster is stationary so the kinetic energy would be zero, but it is at the top of ramp so the potential energy would be high as its gravitational  so it would have to be A

6 0
2 years ago
A student is building a simple circuit with a battery, light bulb, and copper wires. When she connects the wires to the battery
denis23 [38]
It’s will be B because the circuit had a open or close so if that doesn’t work than it’s because it’s open
5 0
3 years ago
Read 2 more answers
How long will it take to go 150km traveling at 50km/hr? step by step please
Zigmanuir [339]
To find out time, you put distance over speed. So you would have to put 150 over 50. You divide 150 by 50 and you would get 3. So your answer is 3 hours.
3 0
3 years ago
A race car has a centripedal acceleration of 13.33M/S as it goes around a curve. If the curve is a circle with radius 30 m, what
agasfer [191]

Answer:19.997m/s

Explanation:

Velocity=√(centripetal acceleration×radius)

Velocity=√(13.33×30)

Velocity=√(399.9)

Velocity=19.997

8 0
3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

#SPJ10

3 0
2 years ago
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