Answer:
Answer : (1) :-
Volume of water filled in the pycnometer is given as = 9.9872 mL.
Mass of pycnometer when filled with water = 23.1148 g.
Mass of empty pycnometer = 13.1455 g.
So, mass of water = (23.1148 - 13.1455) g. = 9.9693 g.
We know that,
<em> Density = Mass / Volume = (9.9693 g.) / (9.9872 mL) = </em>0.998 g/mL.
<u>It is observed that the density of water is evaluated to be 0.998 g/mL. We know that, at 4℃ the density of water becomes maximum i.e. 1 g/mL. On the other hand the temperature at which the density of water is 0.998 g/mL is 0℃. Therefore, it can be concluded that the experiment was performed at a temperature of 0℃.</u>
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Answer:
B
Explanation:
I think that's it.. hope I helped you
Answer:
water at 0C
Explanation:
The colder the water is, the denser it is, so the water here with the lowest temperature, is 0C
<u>Given:</u>
Change in internal energy = ΔU = -5084.1 kJ
Change in enthalpy = ΔH = -5074.3 kJ
<u>To determine:</u>
The work done, W
<u>Explanation:</u>
Based on the first law of thermodynamics,
ΔH = ΔU + PΔV
the work done by a gas is given as:
W = -PΔV
Therefore:
ΔH = ΔU - W
W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ
Ans: Work done is -9.8 kJ
