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melisa1 [442]
3 years ago
8

Given the following system of equations:

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

(D) Divide the first equation, -4x + 8y = 16 , by 2.

Step-by-step explanation:

Given:

-4x + 8y = 16 \ \ \ \ equation \ 1

2x + 4y = 8 \ \ \ \ equation \ 2

We need to find the operation performed on equation so as to get resultant equation as:

-2x + 4y = 8

2x + 4y = 8

From Above we can see that there is no change in equation 2 with respect to resultant equation.

Also Resultant equation is simplified form of equation 1.

Simplifying equation 1 we get;

-4x + 8y = 16

We can see that 2 is the common multiple on both side.

Hence we will divide equation 1 with 2 we get

\frac{-4x}{2}+\frac{8y}{2}=\frac{16}{2}\\\\-2x+4y=8

which is the resultant equation.

Hence (D) Divide the first equation, -4x + 8y = 16 , by 2 is the correct option.

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