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Luba_88 [7]
3 years ago
6

An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance

does the object traverse while accelerating?
Physics
2 answers:
Misha Larkins [42]3 years ago
6 0

Answer:

Distance = speed * time

the formula S =ut +1/2at^2 or S =( v +u)/2*t

where u is initial velocity and v is final velocity

where a is acceleration due to gravity and where t is time

Explanation:

Tcecarenko [31]3 years ago
4 0

Answer: 90m

Explanation:

Use Equation for distance:

S=a*t²/2

use eqation for acceleraton a=(Vf-Vs)/t

Vs- starting speed

Vf - final speed

a-accelaration

---------------------------------

a=5m/s²

Vs=0m/s

Vf=30m/s

use

a=(Vf-Vs)/t

to find time

t=(Vf-Vs)/a

t=30m/s/5m/s²

t=6s

Now calculate distance that object travel using:

S=(a*t²)72

s=(5m/s²*(6s)²)/2

S=90m

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