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Luba_88 [7]
3 years ago
6

An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance

does the object traverse while accelerating?
Physics
2 answers:
Misha Larkins [42]3 years ago
6 0

Answer:

Distance = speed * time

the formula S =ut +1/2at^2 or S =( v +u)/2*t

where u is initial velocity and v is final velocity

where a is acceleration due to gravity and where t is time

Explanation:

Tcecarenko [31]3 years ago
4 0

Answer: 90m

Explanation:

Use Equation for distance:

S=a*t²/2

use eqation for acceleraton a=(Vf-Vs)/t

Vs- starting speed

Vf - final speed

a-accelaration

---------------------------------

a=5m/s²

Vs=0m/s

Vf=30m/s

use

a=(Vf-Vs)/t

to find time

t=(Vf-Vs)/a

t=30m/s/5m/s²

t=6s

Now calculate distance that object travel using:

S=(a*t²)72

s=(5m/s²*(6s)²)/2

S=90m

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A girl running around a circular track of radius 200 m completes one
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Answer:

v = 2 m/s

Explanation:

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Now, for the average velocity of the girl we can use the following formula:

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where,

r = radius = 200 m

therefore,

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3 years ago
A car starts from rest and accelerates from u seconds until it reaches a speed of 10ms
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10x10^-3 *u + 10x10^-3 * 2u = 125

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If the mass of an object is 14 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?
mixas84 [53]

Using the formula:

w = m x g ....... eq1

here w is weight of the object.

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 14 lbm (given)

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Now, substituting the values in equation (1):

w = 14lbm x 32.0 ft/s^{2} = 448 lbm ft/s^{2}

since, 1 lbf = 32.174 lbm ft/s^{2}

so, w = 448 x \frac{1}{32.174}

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Hence, the mass of an object is 13.924 lbf.

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