1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetoff [14.1K]
3 years ago
9

Please help me!! Need this done before the 40 min end

Physics
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

its c

Explanation:

bc i know

You might be interested in
A campus bird spots a member of an opposing football team in an amusement park. The football player is on a ride where he goes a
kenny6666 [7]

Answer:

No..

Explanation:

As the bird releases the drop there is no internal force which will drive it into circular path but it will fall on tangent of the arc at the point of release because it has a tangential velocity same as bird. Path will be parabola in vertical plane.

As the person is on circular arc constantly moving it will never meet that drop.

6 0
3 years ago
A 200-foot tall monument is located in the distance. From a window in a building, a person determines that the angle of elevatio
egoroff_w [7]

Answer:

665 ft

Explanation:

Let d be the distance from the person to the monument. Note that d is perpendicular to the monument and would make 2 triangles with the monuments, 1 up and 1 down.

The side length of the up right-triangle knowing the other side is d and the angle of elevation is 13 degrees is

dtan13^0 = 0.231d

Similarly, the side length of the down right-triangle knowing the other side is d and the angle of depression is 4 degrees

dtan4^0 = 0.07d

Since the 2 sides length above make up the 200 foot monument, their total length is

0.231d + 0.07d = 200

0.301 d = 200

d = 200 / 0.301 = 665 ft

7 0
3 years ago
A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. its initial position
Nesterboy [21]

The position of the object at time t =2.0 s is <u>6.4 m.</u>

Velocity vₓ of a body is the rate at which the position x of the object changes with time.

Therefore,

v_x= \frac{dx}{dt}

Write an equation for x.

dx=v_xdt\\ x=\int v_xdt

Substitute the equation for vₓ =2t² in the integral.

x=\int v_xdt\\ =\int2t^2dt\\ =\frac{2t^3}{3} +C

Here, the constant of integration is C and it is determined by applying initial conditions.

When t =0, x = 1. 1m

x= \frac{2t^3}{3} +C\\ x_0=1.1\\ x= (\frac{2t^3}{3} +1.1)m

Substitute 2.0s for t.

x= (\frac{2t^3}{3} +1.1)m\\ =\frac{2(2.0)^3}{3} +1.1\\ =6.43 m

The position of the particle at t =2.0 s is <u>6.4m</u>




5 0
3 years ago
Help me please........................
stepan [7]

Answer:

Left

Explanation:

3 0
3 years ago
SOMEONE PLEASE HELP PLEASE PLEASE
Black_prince [1.1K]
Ais the correct answer
4 0
3 years ago
Other questions:
  • In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
    9·1 answer
  • A bicycle is heading west. It goes 500m in 5 minutes. What is its velocity?
    12·2 answers
  • Block A is also connected to a horizontally-mounted spring with a spring constant of 281 J/m2. What is the angular frequency (in
    11·1 answer
  • Ulesr...<br> 4.What makes the molecular shape of Co, and NH, different? (2 points)<br> luence.
    7·1 answer
  • Free Brainliest. Who is faster, Sonic or the car from back to the future?
    11·2 answers
  • The difference between a Scalar quantity and a Vector quantity?
    5·1 answer
  • Thanks+ BRAINLIST only for correct answers
    15·2 answers
  • discuss four contributing factors that may lead to an increase of learners abusing substance in scools​
    8·1 answer
  • 8. Placing your vehicle between the pilot/escort vehicle and an oversize/overweight vehicle can be dangerous.A. TrueB. False
    6·1 answer
  • The voltage across the secondary winding is 10,000 v, and the voltage across the primary winding is 25,000 v. if the primary win
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!