Heat is transferred from the sun-warmed surface of the earth to the cooler overlying troposphere via <u>conduction.</u>
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<h3>Heat transfer from earth to atmosphere:</h3>
Conduction, convection, latent heating, and water phase transitions all help to carry heat from the Earth's surface, which has been warmed by the Sun, to the cooler troposphere above.
Latent heat flux is the worldwide transfer of latent heat energy via water and air currents. Here, we demonstrate how air circulation transports latent heat energy horizontally to cooler regions, where it condenses into rain or is deposited as snow, releasing the heat energy that was previously trapped there.
When air is heated from below by sunshine or by coming into contact with a warmer land or sea surface, convection occurs and the air below becomes less dense than the air above.
Learn more about Latent heat here:
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Answer:
Required distance is 103 miles and the required time is 1 hour
Explanation:
Given;
speed of the car, v = 103 miles per hour
Speed is the given as the ratio of distance traveled to time taken for the motion.
The distance it will take another car to catch up to them from a complete stop is 103 miles and the time it will take the car is 1 hour.
Therefore, required distance is 103 miles and the required time is 1 hour.
The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength. That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave.
Answer:
efficiancy=40 percent
Explanation:
efficiency=energy output/energy input×100
efficiancy=8J/20J×100
efficiancy=0.4×100
efficiancy=40 percent
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Complete question:
A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity after 10s ?
Answer:
the final velocity of the train is 4 m/s.
Explanation:
Given;
initial velocity of the train, u = 44 m/s
acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)
time of motion, t = 10 s
let the final velocity of the train = v
The final velocity of the train is calculated using the following kinematic equation;
v = u + at
v = 44 + (-4 x 10)
v = 44 - 40
v = 4 m/s
Therefore, the final velocity of the train is 4 m/s.