Answer:
The total rate at which electrical energy is dissipated by the two resistors is 48 W.
The given parameters;
First resistor, R₁ = 25 ohm
Second resistor, R₂ = 15 ohm
power dissipated in the first resistor, P₁ = 36 W
In series circuit arrangement, the current flowing in each resistor is the same.
The current flowing in the first resistor is calculated as follows;
P = I²R₁
The equivalent resistance of the series arrangement is calculated as;
R = R₁ + R₂
R = 25 + 15
R = 40 ohms
The total rate at which electrical energy is dissipated by the two resistors;
P = I²R
P = 1.2(40)
P = 48 W
Thus, the total rate at which electrical energy is dissipated by the two resistors is 48 W.
Explanation: