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2 years ago

The weakest type of friction that occurs between solid surfaces is _____ friction

Physics

2 answers:

irga5000 [103]2 years ago

8 0

Rolling friction, hope this helps

Evgen [1.6K]2 years ago

4 0

Answer:

Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.

Explanation:

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A pair of slits separated by 1 mm, are illuminated with monochromatic light of wavelength 411 nm. The light falls on a screen 1.

Ilya [14]

Answer:

$t = 0.192 \mu m$

Explanation:

Path difference due to a transparent slab is given as

$\Delta x = (\mu - 1) t$

here we know that

$\mu = 1.79$

now total shift in the bright fringe is given as

$Shift = \frac{D(\mu - 1)t}{d}$

Also we know that the fringe width of maximum intensity is given as

$\delta x = \frac{\lambda D}{d}$

now we have

$\frac{D}{d} = \frac{\delta x}{\lambda}$

now the shift is given as

$Shift = \frac{(\mu - 1) t \delta x}{\lambda}$

given that the shift is

$Shift = 0.37 \delta x$

here we have

$0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}$

now plug in all values in it

$0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}$

$t = 0.192 \times 10^{-6} m$

$t = 0.192 \mu m$

3 0

3 years ago

What is refraction?

Damm [24]

B- light bends as it passes through an object ( a would be reflect)

4 0

2 years ago

9. Ripening is a _______________ and spoiling is a ______________.

IrinaK [193]

Answer:

Explanation:

Chemical reaction,physical

6 0

1 year ago

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In a water park, people walk a distance of 20 meters up an inclined ramp before getting on a water slide. If the spot from where

Elenna [48]

Thank you for posting your Physics question here. I hope the answer helps. Upon calculating the ramp with the horizontal the answer is 20.49 Deg. Below is the solution:

Y = 7 m.
r = 20 m. 

sinA = Y/r = 7/20 = 0.35. 
A = 20.49 Deg.

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2 years ago

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According to the graph, how many atoms would remain after two half-lives?

Fudgin [204]

Answer:

Let No be initial no of atoms

N = N0 / 2 after 1 half-life

N = N0 / 4 after 2 half-lives

So after 2 half-lives 20 of the 80 atoms remain

4 0

2 years ago