A 60 kg person runs up a set of stairs in B-Building 6 meters high, in a time of 8 seconds.

A health care provider suspects a client has developed posttraumatic stress disorder (PTSD). Select the necessary criterion to v

julia-pushkina [17]

Answer:

The necessary criterion to validate the PTSD (posttraumatic stress disorder) is criterion A, (one required): the person was exposed to: death, threatened death, actual or threatened serious injury, or actual or threatened sexual violence,one symptom (or more): inability to remember an important aspect of the event, from criterion B, one symptom (or more): wars survivors, persistent and exaggerated negative beliefs about oneself, others, or the world, and persistent negative emotional state.to criterion C: old age abused; persistent distorted cognitions about the cause or consequences of the event.

Explanation:

DSM-5 PTSD diagnosis measures, assesses, or evaluates dissociative subtypes, which causes disconnection from the surrounding world or from oneself.

The DSM-5 manual, for the PTSD diagnosis, includes the DSM-IV/ICD-9 309.81 to the ICD-10 F43.10.

An experienced mental health provider, such as a psychiatrist or psychologist, is generally in charge of the diagnosis.

To be diagnosed with PTSD, an adult must have at least one avoidance symptom re-experiencing symptom for at least 1 month.

8 0

3 years ago

Who wrote the universal gravitation

ira [324]

I think it was Isaac Newton

3 0

3 years ago

a block of mass m slides along a frictionless track with speed vm. It collides with a stationary block of mass M. Find an expres

shusha [124]

Answer:

Part a) When collision is perfectly inelastic

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b) When collision is perfectly elastic

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

Explanation:

Part a)

As we know that collision is perfectly inelastic

so here we will have

$mv_m = (m + M)v$

so we have

$v = \frac{mv_m}{m + M}$

now we know that in order to complete the circle we will have

$v = \sqrt{5Rg}$

$\frac{mv_m}{m + M} = \sqrt{5Rg}$

now we have

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b)

Now we know that collision is perfectly elastic

so we will have

$v = \frac{2mv_m}{m + M}$

now we have

$\sqrt{5Rg} = \frac{2mv_m}{m + M}$

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

6 0

4 years ago

On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per

Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

$V_{avg} = \frac{Final \ position\ - \ Initial \ position}{final \ time\ - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\ - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr$

Therefore, the average velocity is 180 km/hr

3 0

3 years ago

A bullet of mass 6.20 10-3 kg, moving at 1320 m/s impacts a tree stump and penetrates 11.00 cm into the wood before coming to re

sladkih [1.3K]

Answer:

F = -49.1 10³ N

Explanation:

Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant

$v_{f}$ ² = v₀² + 2 a x

Since the bullet is at rest, the final speed is zero

x = 11.00 cm (1 m / 100 cm) = 0.110 m

0 = v₀² + 2 a x

a = -v₀² / 2 x

a = -1320²/(2 0.110)

a = -7.92 10⁶ m / s²

With Newton's second law we find the force

F = m a

F = 6.20 10⁻³ (-7.92 10⁶)

F = -49.1 10³ N

The sign means that it is the force that the tree exerts to stop the bullet

8 0

3 years ago