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3 years ago

SOMEONE PLZZZZ HELP ME! ITS WORTH 12 POINTS AND BRAINLEST! What is the area of one of the triangular faces

Mathematics

2 answers:

aleksklad [387]3 years ago

7 0

Ok so I’m not perfect at geometry but I have recommendations of apps to use. You can use Socratic, Photomath, and Slader!

dmitriy555 [2]3 years ago

3 0

Answer:

The answer is

Step-by-step explanation:

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Miss Chambers bought 5 pens for $255, if she made a profit of $3 each per pen how much did she sell a pen for?

Natasha2012 [34]

Answer:

$54

Step-by-step explanation:

First, we calculate the amount she paid for each pen.

$255/5 = $51

She paid $51 for each pen.

She made a profit of $3 per pen, so she sold each pen for $51 + $3 = $54

Answer: $54

6 0

3 years ago

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20. Determine the rate of change for the following equation on the given interval.

BigorU [14]

-2<x<3 | *2
-4<2x<6 | +7
3< 2x+7< 13

3<10<13

The answer is C

4 0

3 years ago

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The quadratic function h(t) = -16t^2 + 120 represents the height of 120 feet. what is the height of the object after 1.5 seconds

Anettt [7]

Answer:

84 feet

Step-by-step explanation:

-16(1.5)^2+120=84

5 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

Linear function whose graph has a slope of 7

Inessa05 [86]

Answer:

y=7x?

Step-by-step explanation:

just a slope of 7 here, but you could add some # like y=7x+4

8 0

3 years ago

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