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velikii [3]
3 years ago
6

Which of the following reactions is the least energetic? Question 18 options: ATP + H2O → ADP + Pi ATP + H2O → AMP + PPi AMP + H

2O → Adenosine + Pi ADP + H2O → AMP + Pi All give off the same amount of energy.
Chemistry
1 answer:
Mama L [17]3 years ago
8 0

Answer:

The correct answer is AMP+H2O→ Adenosine + pi

Explanation:

The above reaction is least energetic because there is no phosphoanhydride bond present with adenosine mono phosphate.Phospho anhydride bond is an energy rich bond.

As a result hydrolysis of AMP generates very little amount of energy in comparison to the hydrolysis of ATP and ADP.

   

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3 0
2 years ago
Please Balanced this Equation
Scilla [17]

Answer:

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

Explanation:

Consider the oxidation state on each of the element:

Left-hand side:

  • O: -2 (as in most compounds);
  • Cr: \displaystyle \frac{1}{2}(\underbrace{-2}_{\text{ion}} - \underbrace{7\times (-2)}_{\text{Oxygen}}) = +6;
  • Fe: +2 (from the charge of the ion);

Right-hand side:

  • Cr: +3;
  • Fe: +3.

Change in oxidation state:

  • Each Cr atom: decreases by 3 (reduction).
  • Each Fe atom: increases by 1 (oxidation).

Changes in oxidation states shall balance each other in redox reactions. Thus, for each Cr atom on the left-hand side, there need to be three Fe atoms.

Assume that the coefficient of the most complex species \rm Cr_2O_7^{2-} is 1. There will be two Cr atoms and hence six Fe atoms on the left-hand side. Additionally, there are going to be seven O atoms.

Atoms are conserved in chemical reactions. As a result, the right-hand side of this equation will contain

  • two Cr atoms,
  • six Fe atoms, and
  • seven O atoms.

O atoms seldom appear among the products in acidic environments; they rapidly combine with \rm H^{+} ions to produce water \rm H_2O. Seven O atoms will make seven water molecules. That's fourteen H atoms and hence fourteen \rm H^{+} ions on the product side of this equation. Hence the balanced equation. Double check to ensure that the charges on the ions also balance.

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

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3 years ago
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Answer:

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