Ask question

Ask question

All categories

3 years ago

9

As a human resources professional for a large company, Tommy is involved with the ___________ process. His goal is to find the r

ight number of qualified people at the right time. He will screen a qualified pool of candidates and send these individuals forward to others in the firm who will make the final selection decision.

1 answer:

zaharov [31]3 years ago

4 0

Answer:

Recruitment

Explanation:

The process of recruitment involves several activities whose main objective is to get the right people with relevant qualifications at the appropriate time to meet the needs of an organisation whenever there’s need. The process involves screening a pool of candidates through several steps to obtain the best fit for the job.

You might be interested in

The hull of a vessel develops a leak and takes on water at a rate of 57.5 gal/min. When the leak is discovered the lower deck is

leva [86]

Answer:

It will be around 146,27 min since the pump is turned on until the deck is clear of the water.

Explanation:

When the leak is discovered and the pump is turned on, the lower deck is already submerged and the leak is not fixed; then, in order to have the deck clear of water, the bilge pump has to remove the <em>accumulated water </em>( $V_{0}$ ) and the <em>water that is taking on</em> ( $r_{in}*t$ ) through the leak. We can represent this mathematically as follow:

$V_{0} +r_{in} *t-r_{out}*t=0$ <em>Equation 1</em>

Where:

$V_{0}$ : is the accumulated water when the leak was discovered

$r_{in}$ : is the takes on rate through the leak = 57.5 gal/min

$r_{out}$ : is the removing rate of the bilge pump = 73.8 gal/min

t= is the time since the pump is turned on until the deck is clear of water.

To calculate the accumulated water ( $V_{0}$ ), we will model the lower deck as a flat-bottomed container with a bottom surface area of 510 $ft^{2}$ and straight vertical sides. Knowing that the level submerged is 7.5 inches, and performing the corresponding unit conversions, we obtain:

$V_{0}$ = bottom surface area * lever submerged

$V_{0}= 510ft^{2}*7.5 in*\frac{1ft}{12in}=318.75 ft^{3}*7.48\frac{gal}{1ft^{3}}=2384.25 gal$ <em>Equation 2</em>

Solving equation 1 for time (t), and replacing the value obtained in equation 2, we get:

$t=\frac{V_{0}}{(r_{out}-r_{in})} =\frac{2384.25 gal}{(73.8-57.5)gal/min}=$ 146,27 min

8 0

3 years ago

A shaft made of stainless steel has an outside diameter of 42 mm and a wall thickness of 4 mm. Determine the maximum torque T th

fiasKO [112]

Answer:

Explanation:

Using equation of pure torsion

$\frac{T}{I_{polar} }=\frac{t}{r}$

where

T is the applied Torque

$I_{polar}$ is polar moment of inertia of the shaft

t is the shear stress at a distance r from the center

r is distance from center

For a shaft with

$D_{0} =$ Outer Diameter

$D_{i} =$ Inner Diameter

$I_{polar}=\frac{\pi (D_{o} ^{4}-D_{in} ^{4}) }{32}$

Applying values in the above equation we get

$I_{polar} =\frac{\pi(0.042^{4}-(0.042-.008)^{4})}{32}\\I_{polar}= 1.74$ x $10^{-7} m^{4}$

Thus from the equation of torsion we get

$T=\frac{I_{polar} t}{r}$

Applying values we get

$T=\frac{1.74X10^{-7}X100X10^{6} }{.021}$

T =829.97Nm

7 0

3 years ago

(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length

EastWind [94]

This question is incomplete, the complete question is;

(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 2 $l$ . The flow is laminar and fully developed. The pressure drop for the first pipe is 1.657 times greater than it is for the second pipe. If the diameter of the first pipe is D, determine the diameter of the second pipe.

D₃ = _____D.

{ the tolerance is +/-3% }

Answer:

the diameter of the second pipe D₃ is 1.13D

Explanation:

Given the data in the question;

Length = 2 $l$

pressure drop in the first pipe is 1.657 times greater than it is for the second pipe.

Now, we know that for Laminar Flow;

V' = πD⁴ΔP / 128μL

where V'₁ = V'₂ and ΔP₁₋₂ = 1.657 ΔP₂₋₃

Hence,

V'₁ = πD⁴ΔP₁₋₂ / 128μL = V'₃ = πD₃⁴ΔP₂₋₃ / 128μL

so

D₃ = D $($ ΔP₁₋₂ / ΔP₂₋₃ $)^{\frac{1}{4}$

we substitute

D₃ = D $($ 1.657 $)^{\frac{1}{4}$

D₃ = D( 1.134568 )

D₃ = 1.13D

Therefore, the diameter of the second pipe D₃ is 1.13D

8 0

3 years ago

It is said that Archimedes discovered the buoyancy laws when asked by King Hiero of Syracuse to determine whether his new crown

sertanlavr [38]

Answer with Explanation:

The crown will be pure if it's specific gravity is 19.3

Now by definition of specific gravity it is the ratio between the weight of an object to the weight of water of equal volume

Since it is given that the weight of the crown is 11.8 N we need to find it's volume

Now According to Archimedes principle when the crown is immersed into water the water shall exert a force in upwards direction on the crown with a magnitude equaling to weight of the water displaced by the crown

Mathematically this is the difference between the weight of the crown in air and weight when immersed in water

Thus Buoyant force is $F_{B}=11.8-10.9=0.9N$

Now by Archimedes principle This force equals in magnitude to the weight of water of same volume as of the crown

Thus the specific gravity of the crown equals

$S.G=\frac{11.8}{0.9}=13.11$

As we see that the specific gravity of the crown material is less than that of pure gold hence we conclude that it is impure.

4 0

4 years ago

Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q

Charra [1.4K]

Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es

$C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}$

Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

ΔV = - E d

E = - $\frac{\Delta V}{d}$

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

E = $- \frac{\Delta V}{d_1}$

Capacitor 2

d₂ = 2 d₁

E₂ = $- \frac{\Delta V}{2d_1}$

E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor

Q = ε₀ $\frac{A \Delta V}{d}$

Capacitor 1

Q₁ = (ε₀ A ΔV) $\frac{1}{d_1}$

Capacitor 2

Q₂ = (ε₀ A Δv) $\frac{1}{2d_1}$

Q₂ = Q₁/2

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

$u_E$ = ½ ε₀ E²

calculamos para cada capacitor

Capacitor 1

$u_{E\ 1}$ = ½ ε₀ E₁²

Capacitor 2

$u_{E 2}$ = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mas densidad de carga

Aprender mas aquí: brainly.com/question/22813371

7 0

3 years ago