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balandron [24]
3 years ago
12

Name the ferrous metal that most workshop tools are made from??

Engineering
2 answers:
yaroslaw [1]3 years ago
6 0
Either iron or steel
dedylja [7]3 years ago
5 0
Hey I searched this up for you this is what I found! “Most are made of steel or cast iron, but in each case the alloy has been carefully chosen and the processing tailored to the application.”
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How much force is required if the ramp is 15 ft long
lord [1]

Answer:

do yah stiil need help

Explanation:

6 0
2 years ago
A wall that cannot be moved because it is carrying the weight of the roof is considered a wall
ad-work [718]

Answer:

Blank wall

Explanation:

A wall that cannot be moved because it is carrying the weight of the roof is considered a blank wall.

5 0
2 years ago
The maximum voltage in a cooling system should not exceed ______ volts.
Natali [406]

Answer:2%

When the voltages between the three phases are not equal, the current increases dramatically in the motor winding's, and if allowed to continue, the motor will be damaged.

Explanation:

7 0
1 year ago
If the surface energy of a magnesium oxide - nickel oxide (MgO-NiO) solid solution is 1.05 J/m2 and its elastic modulus is 198 G
Nastasia [14]

Answer:

The maximum length is 3.897×10^-5 mm

Explanation:

Extension = surface energy/elastic modulus

surface energy = 1.05 J/m^2

elastic modulus = 198 GPa = 198×10^9 Pa

Extension = 1.05/198×10^9 = 5.3×10^-12 m

Strain = stress/elastic modulus = 27×10^6/198×10^9 = 1.36×10^-4

Length = extension/strain = 5.3×10^-12/1.36×10^-4 = 3.897×10^-8 m = 3.897×10^-8 × 1000 = 3.897×10^-5 mm

7 0
3 years ago
Determine the voltages at all nodes and the currents through all branches. Assume that the transistor B is 100,
iren [92.7K]

Answer:

The voltages of all nodes are, IE = 4.65 mA, IB =46.039μA,  IC=4.6039 mA, VB = 10v, VE =10.7, Vc =4.6039 v

Explanation:

Solution

Given that:

V+ = 20v

Re = 2kΩ

Rc = 1kΩ

Now we will amke use of the method KVL in the loop.

= - Ve + IE . Re + VEB + VB = 0

Thus

IE = V+ -VEB -VB/Re

Which gives us the following:

IE = 20-0.7 - 10/2k

= 9.3/2k

so, IE = 4.65 mA

IB = IE/β +1 = 4.65 m /101

Thus,

IB = 0.046039 mA

IB = 46.039μA

IC =βIB

Now,

IC = 100 * 0.046039

IC is 4.6039 mA

Now,

VB = 10v

VE = VB + VEB

= 10 +0.7 = 10.7 v

So,

Vc =Ic . Rc = 4.6039 * 1k

=4.6039 v

Finally, this is the table summary from calculations carried out.

Summary Table

Parameters          IE       IC           IB            VE       VB         Vc

Unit                     mA     mA          μA            V           V          V

Value                  4.65    4.6039   46.039    10.7      10     4.6039

4 0
2 years ago
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