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3 years ago

12

Name the ferrous metal that most workshop tools are made from??

2 answers:

yaroslaw [1]3 years ago

6 0

Either iron or steel

dedylja [7]3 years ago

5 0

Hey I searched this up for you this is what I found! “Most are made of steel or cast iron, but in each case the alloy has been carefully chosen and the processing tailored to the application.”

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A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli

Scrat [10]

Answer:

$X_t=2.17391304*10^{-4}$

$X_r=2.89855072*10^{-4}$

$e_t=0.0026$

$e_r=0.0035$

Explanation:

From the question we are told that:

Dimension $12*12$

Thickness $l_t=5mm=5*10^-3$

Normal tensile force on top side $F_t= 15kN$

Normal tensile force on right side $F_r= 20kN$

Elastic modulus, $E=115Gpap=>115*10^9$

Generally the equation for Normal Strain X is mathematically given by

$X=\frac{Force}{Area*E}$

Therefore

For Top

$X_t=\frac{Force_t}{Area*E}$

Where

$Area=L*B*T$

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}$

$X_t=2.17391304*10^{-4}$

For Right side $X_r=\frac{Force_r}{Area*E}$

Where

Area=L*B*T

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_r=2.89855072*10^{-4}$

$X_r=2.89855072*10^{-4}$

Generally the equation for elongation is mathematically given by

$e=strain *12$

For top

$e_t=2.17391304*10^{-4}*12$

$e_t=0.0026$

For Right

$e_r=2.89855072*10^{-4} *12$

$e_r=0.0035$

5 0

3 years ago

Against which type of economic structure does conflict theory argue?

alisha [4.7K]

Answer:

b) socialism

Explanation:

Conflict theory focuses on the competition between groups within society over limited resources. Conflict theory views social and economic institutions as tools of the struggle between groups or classes, used to maintain inequality and the dominance of the ruling class.

HOPE IT HELPS!!!!!!!!!

4 0

3 years ago

Elena, the marketing manager at a consumer goods company, plans to send out questionnaires to random individuals (consumers) in

motikmotik

Answer:

A. Qualitative

Explanation:

Because they're looking for qualities to change in future products

7 0

3 years ago

Fluids at rest possess no flow energy. a)- True b)- False

gtnhenbr [62]

Answer:

True.

Explanation:

According the engineering flow they don not possess flow energy when they are in rest.

When they are in motion they show a translation energy.

The features if fluids may be different according the variables of pressure and temperature.

8 0

3 years ago

A thick casting with a thermal diffusivity of 5 x 10-6 m2/s is initially at a uniform temperature of 150oC. One surface of the c

fredd [130]

Answer:

$T_o = 141.81 ^0C$

Explanation:

Given that;

Thermal diffusivity $\alpha = 5 \times 10 ^{-6} m^2/s$

Thermal conductivity $k = 20 \ W/m.K$

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the temperature at the surface at a depth of 20 mm after 40 seconds.

$Bi = \dfrac{hL}{k}$

$Bi = \dfrac{20*0.02}{20}$

Bi == 0.02

$\tau = \dfrac{\alpha t}{L^2}$

$\tau= \dfrac{5*10^{-6 }* 40}{0.020^2}$

$\tau = 0.5$

For a wall at 0.2 Bi

$A_1 = 1.0311$

$\lambda _1 = 0.4328$

Therefore;

$\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )$

$\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085$

$\dfrac{T_o - 293 }{130}= 0.937$

$T_o - 293= 0.937 \times 130$

$T_o - 293= 121.81$

$T_o = 121.81+ 293$

$T_o = 414.81 \ K$

$T_o = (414.81 - 273)^0C$

$T_o = 141.81 ^0C$

4 0

4 years ago