Calculate k′, the equilibrium constant, for the system 1/2h2+fdox→fdred+h+.

given a k value of 0.43 for the following aqueous equilibrium suppose sample z is placed into water such that its original conce

serious [3.7K]

Answer:

Less than 0.033 M:

$[Z]_{eq}=2.4x10^{-3}M$

Explanation:

Hello,

In this case, the described equilibrium is:

$2A+B\rightarrow 2Z$

Thus, the law of mass action is:

$K=\frac{[Z]^2}{[A]^2[B]}=0.43$

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

$\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33$

Know, by introducing the change $x$ due to the reaction extent, we can write:

$2.33=\frac{(2x)^2*x}{(0.033-2x)^2}$

Which has the following solution:

$x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M$

But the correct solution is $x_3=0.0152M$ since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

$[Z]_{eq}=0.033M-2(0.0153M)$

$[Z]_{eq}=2.4x10^{-3}M$

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

6 0

3 years ago

The explosions that take place during a fireworks show are an example of which of the following?Image of fireworks exploding in

babymother [125]

Chemical change
:)
hope this helps

4 0

3 years ago

Read 2 more answers

How do you balance this equation?

Margarita [4]

Answer:

Al4C3 + 12H2O = 3CH4 + 4Al(OH)3

Explanation:

Not sure if any explanation is needed but always start with the most complex compound. In this case it is Al(OH)3. You can see that there is 4 Aluminiums on the other side so I would start by putting a 4 next to the Al(OH)3. This now gives me 12 Hydrogens and 12 Oxygens on the right side. I put a 3 next to the CH4 to balance the Carbons on the left side. This leaves me with 12 Oxygens and 24 Hydrogens on the right side. This ends up being perfect because I can put a 12 next to the H2O.

6 0

3 years ago

54:63 ratio simplest form?

MrMuchimi

Answer:

The fraction is 6/7

Explanation:

6/7 is the simplified fraction for 54/63 by using the GCD or HCF method. Thus, 6/7 is the simplified fraction for 54/63 by using the prime factorization method.

Hope this helps!!!

Can I have Brainliest???

3 0

3 years ago

socratic For the following reaction, 25.6 grams of hydrochloric acid are allowed to react with 52.4 grams of barium hydroxide .

TEA [102]

Answer:

63.7g BaCl₂

Explanation:

Based on the chemical reaction:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

2 moles of HCl reacts per mole of barium hydroxide

To solve this question, we need to convert the moles of each reactant to moles and, using the chemical reaction, find limiting reactant as follows:

Moles Ba(OH)₂ - Molar mass: 171.34g/mol-

52.4g Ba(OH)₂ * (1mol / 171.34g) = 0.306 moles Ba(OH)₂

Moles HCl - Molar mass: 36.46g/mol-

25.6g HCl * (1mol / 36.46g) = 0.702 moles HCl

For a complete reaction of 0.702 moles HCl are required:

0.702 moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.351 moles of Ba(OH)₂

As there are just 0.306 moles, limiting reactant is Ba(OH)₂

That means the maximum amount of BaCl₂ produced is:

0.306 moles Ba(OH)₂ * (1mol BaCl₂ / 1 mol Ba(OH)₂) = 0.306 moles BaCl₂

In mass -Molar mass BaCl₂: 208.23g/mol-

0.306 moles BaCl₂ * (208.23g / mol) = 63.7g BaCl₂

3 0

3 years ago