Once you identify the compound as Ionic<span>, </span>Molecular, or an Acid, follow the individual ... chemicalformulas<span>, write </span>whether<span> the compound is </span>ionic or molecular<span>, and ...</span>
Answer:
LFNC-A
Explanation:
Liquidtight Flexible Non-Metallic Conduit Type LFNC-A is a layered raceway of circular cross section with a smooth flexibly polyvinyl chloride (PVC) inner layer with a reinforcing layer covered with a flexible polyvinyl chloride (PVC) jacket.
1) Answer is: molar mas of ammonia is 17.031 g/mol.
M(NH₃) = Ar(N) + 3 · Ar(H) · g/mol.
M(NH₃) = 14.007 + 3 · 1.008 · g/mol.
M(NH₃) = 17.031 g/mol.
2) Answer is: molar mas of lead(II) chloride is 278.106 g/mol.
M(PbCl₂) = Ar(Pb) + 2 · Ar(Cl) · g/mol.
M(PbCl₂) = 207.2 + 2 · 35.453 · g/mol.
M(PbCl₂) = 278.106 g/mol.
3) Answer is: molar mas of acetic acid is 60.052 g/mol.
M(CH₃COOH) = 2 · Ar(C) + 2 · Ar(O) + 4 · Ar(H) · g/mol.
M(CH₃COOH) = 2 · 12.0107 + 2 · 15.9994 + 4 · 1.008 · g/mol.
M(CH₃COOH) = 60.052 g/mol.
Answer:
3.- The same
Explanation:
1.- In the reactants you need to calculate the charges that you have:
2 Al(s) = zero, because the aluminum is in it based formed (that mean without charge).
3 Cu2+ = 3 x 2+ = 6+ That is the total positive charges that copper collaborate in this reaction.
2.- Then calculate the charges on the products:
2 Al3+ = 2 x 3+ = 6+ charges from the aluminum.
3 Cu(s) = zero, because the copper in this case is in the base form
3.- In this way, the charges at the begging (6+) and at the end (6+) are the same.
1) Chemical equation of the equilibrium
BaCrO4⇄ Ba (2+) + CrO4 (2-)
2) Ksp equation
Ksp = [Ba(2+)] [CrO4 (2-)]
where Ksp = 1.0 * 10^ - 10 and [Ba(2+)] = [CrO4(2-)] = x
3) Calculations
1.0 * 10^ -10 = x * x
=> x^2 = 1.10 * 10^-10
=> x = √[1.0 * 10^ -10] = 0.000010
Answer: [Ba(2+)] = [CrO4(2-)] = 0.00001 M
