The mass of NaCl formed is 8.307 grams
<u><em> calculation</em></u>
step 1: write the equation for reaction
Na₂CO₃ + 2HCl → 2 NaCl +CO₂ +H₂O
Step 2: find the moles of Na₂CO₃
moles = mass/molar mass
The molar mass of Na₂CO₃ is = (23 x2) + 12 + ( 16 x3) = 106 g/mol
moles = 7.5 g/106 g/mol =0.071 moles
Step 3: use the mole ratio to determine the mole of NaCl
Na₂CO₃:NaCl is 1:2 therefore the moles of NaCl =0.07 x2 =0.142 moles
Step 4: calculate mass of NaCl
mass= moles x molar mass
the molar mass of NaCl= 23 +35.5 =58.5 g/mol
mass = 0.142 moles x 58.5 g/mol =8.307 grams
Answer:
d
Explanation:
(d the water and metal will adjust to the same temperature between 10 degree c and 120 degree c this temperature will be call equilibrium temperature
Answer:
<h2>2. H2O < CH3OH < CH3CH2OH < C9H20</h2>
Explanation:
Decane is a hydrocarbon so it is a non-polar molecule. Non-polar molecules are soluble in non-polar molecules and polar molecules are soluble in polar molecules. Water is a polar molecule so it is least soluble in decane molecule and 
is a non-polar molecule so it is most soluble in decane molecule. Methanol and ethanol are the derivatives of hydrocarbon so they have more solubility than water but less solubility than nonane molecules.
