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3 years ago

Hydrogen reacts with chlorine to form hydrogen chloride (HCl (g), mc012-1.jpgHf = –92.3 kJ/mol) according to the reaction below.

Chemistry

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer:

A. The enthalpy of the reaction is –184.6 kJ, and the reaction is exothermic.

Explanation:

this is the correct answer on ed-genuity, hope this helps! :)

Kobotan [32]3 years ago

3 0

Given:

H2(g) + Cl2 (g) → 2HCl (g)

To determine:

The enthalpy of the reaction and whether it is endo or exothermic

Explanation:

Enthalpy of a reaction is given by the difference between the enthalpy of formation of reactants and products

ΔH = ∑nHf (products) - ∑nHf (reactants)

= [2Hf(HCl)] - [Hf(H2) + Hf(Cl2)] = 2 (-92.3) kJ = - 184.6 kJ

Since the reaction enthalpy is negative, the reaction is exothermic

Ans: The enthalpy of reaction is -184. kJ and the reaction is exothermic

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0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction

algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce $\frac{2}{1}$ = $\frac{x}{0.50}$

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

$\frac{2}{2}$ = $\frac{x}{0.6}$

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

$\frac{2}{3}$ = $\frac{x}{0.9}$

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0

3 years ago

a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g

leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = $9.77\times \dfrac{22.34}{100}=2.18\ g$ .

Hence , this is the required solution .

7 0

3 years ago

Isotopes: are atoms of different elements which have the same mass are atoms of the same element with equal numbers of neutrons

koban [17]

I can't understand your option because there is no full stop however

isotopes are 2 or more form of elements that contain equal number of proton but different number of neutron in their nuclei

4 0

3 years ago

Read 2 more answers

What is the atomic number of the atom in the diagram above please ?

Daniel [21]

Answer:

Explanation:

The atomic number is the number of protons in an atom. Protons are the positively charged particles in the nucleus. The number of protons define the identity of an element. An element with 5 protons is Boron, no matter how many neutrons may be present.

3 0

3 years ago

a metal object has a mass of 9.0g and a volume of 1.5ml. what is the density of the object? density= mass/volume

weeeeeb [17]

The density of the metal object=6.0 $\frac{g}{m l}$

Given:

Volume of the metal object=1.5ml

Mass of the metal object=9.0g

To find:

Density of the metal object

Step by Step Explanation:

Solution:

According to the formula, Density of the metal object can be calculated as

$\rho=\frac{m}{v}$

Where, m=mass of the metal object

$\rho$ =density of the metal object

v=volume of the metal object

We know the values of v=1.5ml and m=9.0g

Substitute these values in the above equation we get

$\rho=\frac{m}{v}$

$\rho$ =9.0/1.5

=6.0 $\frac{g}{m l}$

Result:

Thus the density of the metal object is 6.0 $\frac{g}{m l}$

4 0

3 years ago