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3 years ago

I NEED HELP PLEASE I WILL MARK BRAINLIST The question is in the screenshot

Mathematics

1 answer:

Ivan3 years ago

4 0

The answer is unreasonable because the value of x is between 2 and 3.The error is : she did not introducing logs in solving the equation.

Step-by-step explanation:

The question is $7^x=95$

Here answers is unreasonable because, she can test with powers of seven like;

7²=49

7³=343

So this means the value of x lies between 2 and 3, so here answer 11.71 is unreasonable

b) In this case, to solve the equation, introduce logs both sides

$7^x=95$

$log7^x=log95\\\\\\xlog7=log95\\\\\\x=\frac{log95}{log7} \\\\\\x=2.340$

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Indices :brainly.com/question/1660321

Keywords :Equation, error

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In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import

Serga [27]

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np = 30×0.56=16.8

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3 years ago

Can you please help me with this

UNO [17]

Parentheses. Exponents. Multiplication Division. Addition Subtraction.

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3 years ago

Find f(3) for f(x) = 1/2(4)^x A. 8 B. 32 C. 6 D. 64

Elza [17]

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3 years ago

Read 2 more answers

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome

Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable X represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), p = 0.52

The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.

(1)

Compute the probability of overbooking as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

$=P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135$

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

$=P(X$

Thus, the probability that the flight has empty seats is 0.4625.

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3 years ago

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vitfil [10]

Answer:

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Step-by-step explanation:

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3 years ago