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konstantin123 [22]
3 years ago
14

Total these measurements. Your answer should indicate the proper accuracy. Be sure to include the units in your answer. (Remembe

r when adding figures, you need to round your answer so that it reflects the figure in the problem with the least amount of significant figures to the right of the decimal if a decimal is present).
2 cm
1 cm
5.3 cm
Physics
1 answer:
Mila [183]3 years ago
5 0
Your answer is 8. You add 2 + 1 + 5.3 to get 8.3. You round down to 8 because of the sig fig rules.
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A battery supplies E volts to a circuit containing a resistor R. How could the current in the resistor be increased? Select all
anastassius [24]

Answer:

I=V/R

so larger bsttery or small resistor can increase the current value.

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Which of the folltrue or false: the ratio of heat exchange in conduction is independent of exposure time.owing techniques uses e
Sliva [168]

True conditions

Efficiency of Heat Exchanger are as below:

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6 0
1 year ago
The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.
S_A_V [24]

Answer:

The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

Explanation:

The angular frequency of a physical pendulum is measured by the following expression:

\omega = \sqrt{\frac{m\cdot g \cdot d}{I_{o}} }

Where:

\omega - Angular frequency, measured in radians per second.

m - Mass of the physical pendulum, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

d - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

I_{O} - Moment of inertia with respect to pivot point, measured in kg\cdot m^{2}.

In addition, frequency and angular frequency are both related by the following formula:

\omega =2\pi\cdot f

Where:

f - Frequency, measured in hertz.

If f = 0.658\,hz, then angular frequency of the physical pendulum is:

\omega = 2\pi \cdot (0.658\,hz)

\omega = 4.134\,\frac{rad}{s}

From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}

I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}

Given that m = 1.15\,kg, g = 9.807\,\frac{m}{s^{2}}, d = 0.425\,m and \omega = 4.134\,\frac{rad}{s}, the moment of inertia associated with the physical pendulum is:

I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}

I_{o} = 0.280\,kg\cdot m^{2}

The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

8 0
3 years ago
Steve and Carl are driving from Scranton to Bridgeport, a distance of 180 miles. If their speed averages 60 miles an hour, how l
Vikki [24]

Time = (distance) / (speed)

Time = (180 miles) / (60 mi/hr)

Time = (180/60) (mi-hr/mi)

<em>Time = 3 hours</em>

4 0
3 years ago
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Which watch is used by scientists for correct measurement of time?
timurjin [86]

Answer:

It’s the atomic clock

Explanation:

3 0
3 years ago
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