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sashaice [31]
3 years ago
10

In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 2.30 104-m length of wire w

as let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of 7.50 103 m/s, and the magnitude of the earth's magnetic field at the location of the wire was 5.40 10-5 T. If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire?
Physics
1 answer:
Nikolay [14]3 years ago
5 0

<h2>emf = 9.3 x 10³</h2>

Explanation:

When a conductor moves in the magnetic field , the emf is generated across its ends . Which can be calculated by the relation

emf  ξ = B x l x v

here B is the magnetic field strength , l is the length of conductor and v is its velocity .

In our question B = 5.4 x 10⁻⁵ T

l = 2.30 x 10⁴ m  and v = 7.5 x 10³

Thus  ξ = 5.4 x 10⁻⁵ x 2.30 x 10⁴ x 7.5 x 10³ = 9.3 x 10³ Volt

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Follows are the solution to this question:

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In point c:

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3 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
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Answer:

Explanation:

Given the simultaneous equation,

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Solving for the value of C and D using substitution method.

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3C/3 =  (5-4D)/3

C = (5-4D)/3 .... 3

From equation 2:

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5D = 2-2C

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5D/5 = 2-2C/5

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To learn more about acceleration, refer to the link brainly.com/question/2437624

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