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lianna [129]
3 years ago
6

Steve and Carl are driving from Scranton to Bridgeport, a distance of 180 miles. If their speed averages 60 miles an hour, how l

ong will it take them to get there
Physics
2 answers:
DaniilM [7]3 years ago
7 0

Answer:

The answer is B

every hour, Steve and Carl cover 60 miles

if they need to cover 180 miles it will take them 3 hours

you can set up a proportion

60/1=180x where x is the amount of hours Steve and Carl will drive to cover 180 miles.

proportion simplifies to this:

60x=180

isolate the varible

60x/60=180/60

x=3

Vikki [24]3 years ago
4 0

Time = (distance) / (speed)

Time = (180 miles) / (60 mi/hr)

Time = (180/60) (mi-hr/mi)

<em>Time = 3 hours</em>

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Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
NISA [10]
The mechanical advantage of a machine is the ratio between the output force and the input force:
MA= \frac{F_O}{F_I}
In our problem, the input force is 100 N, while the output force is the weight of the object the student lifts, 500 N. So, the mechanical advantage is
MA= \frac{500 N}{100 N}=5
7 0
4 years ago
1. What is the kinetic Energy of a 1500kg object moving at 21 m/s?
Wewaii [24]
The formula for working out kinetic energy is

=122

KE = kinetic energy
m = mass of a body
v = velocity of a body


kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

For the first one I think :
Answer:
KE = 330750 J

I’m not sure about the second one- sorry

The third is
Answer:
KE = 41454 J

Hope it helps and it is correct, sorry if it isn’t !
8 0
3 years ago
A 20 kg box rests on the ground. Round all answers to the hundredths, if necessary. What is the weight of the box?​
cricket20 [7]
  • Mass=m=20kg
  • Acceleration due to gravity=10m/s^2

Weight=Applied force

\\ \sf\longmapsto F=mg

\\ \sf\longmapsto F=20(10)

\\ \sf\longmapsto F=200N

5 0
3 years ago
Read 2 more answers
A 1325 kg car and a 2050 kg pickup truck approach a curve on a highway that has a radius of 255 m. At what angle should the high
Scorpion4ik [409]

Answer:

the banking angle of the road is 24.2⁰

Explanation:

Given;

speed of the vehicles considered, v = 75 mi/h

Speed in m/s ⇒ 1 mi/h --------> 0.44704 m/s

                         75 mi/h --------> ?

=   75 x 0.44704 m/s = 33.528 m/s

radius of the curve, r = 255 m

The banking angle of the road is calculated as;

\theta = tan^{-1} (\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{33.528^2}{255\times 9.8} )\\\\\theta  = tan^{-1}(0.44983)\\\\\theta  =24.2^0

Therefore, the banking angle of the road is 24.2⁰

8 0
3 years ago
Suppose the Earth's magnetic field at the equator has magnitude 0.00005 T and a northerly direction at all points. How fast must
sasho [114]

Answer:

Velocity will be v=1.291\times 10^8m/sec

Explanation:

We have given magnetic field B = 0.00005 T

Mass m = 238 U

We know that 1u=1.66\times 10^{-27}kg

So 238 U =238\times 1.66\times 10^{-27}=395.08\times 10^{-27}kg

Radius =R+1.44=6378+1.44=6379.44KM

We know that magnetic force is given by

F=qvB which is equal to the centripetal force

So qvB=\frac{mv^2}{r}

1.6\times 10^{-19}\times v\times 0.00005=\frac{395.08\times 10^{-27}v^2}{6379.44}

v=1.291\times 10^8m/sec

5 0
3 years ago
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