Answer:
Magnitude of displacement = 2.07 km
Magnitude of average velocity = 1.17 kmph
Explanation:
Let east represent positive x axis and north represent positive y axis.
A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north of west.
1.93 km due wast
s ₁ = 1.93 i km
1.03 km due south
s₂ = -1.03 j km
3.84 km in a direction 52.8 ° north of west
s₃ = -3.84 cos 52.8 i + 3.84 sin 52.8 j = -2.32 i + 3.06 j km
Total displacement
s = s ₁+ s₂+ s₃ = 1.93 i - 1.03 j -2.32 i + 3.06 j = -0.39 i + 2.03 j
Magnitude of displacement,
Time taken = 1.771 hour
Magnitude of average velocity,
the force is given by the equation
q*v*B [email protected]
thus it will be
(1.6*10^-19)*(7.8*10^4)*(3)*1/√2 which gives 2.6*10^-14 N
Answer:
The weight would be 71.6kg
Explanation:
Assuming the fluid mostly water and its density 1 kg/L, the new weight is the last recorded weight minus the mass of 1000ml (1l) of the fluid.
so the new weight is:
Answer:
Explanation:
mass of alpha particle, m = 4 u = 4 x 1.67 x 10^-27 kg
charge, q = 2 e = 3.2 x 10^-19 C
radius, r = 3.45 cm
Magnetic field, B = 1.67 T
(a) let v be the speed
v = 2760000 m/s
(b) Let T be the period of revolution
T = 7.85 x 10^-8 seconds
(c) Kinetic energy, K =0.5 x mv²
K = 0.5 x 4 x 1.67 x 10^-27 x 2760000 x 2760000
K = 6.36 x 10^-15 J
(d) kinetic energy, K = e V
where, V is the potential difference
6.36 x 10^-15 = 1.6 x 10^-19 x V
V = 39754.35 V
Answer:
True
Explanation:
The number density of an ideal gas at stp is called the loschmidt number, being named after the Austrian physicist Johann Josef Loschmidt who first estimated this quantity in 1865
n =
where is the Boltzman constant
T is the temperature
P is the pressure
Loschmidt Number is the number of molecules of gas present in one cubic centimetre of it at STP conditions.Loschmidt constant is also used to define the amagat, which is a practical unit of number density for gases and other substances:
1 amagat = n = 2.6867811×1025 m−3,