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Oduvanchick [21]
3 years ago
12

If a spinner is divided into 2 sections is spun 5 times, how many outcomes are possible?

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0
The final number of outcomes would end up being 10 possible outcomes because you would do five and multiply it by two. And there would be a possibility of landing on any of ten outcomes. Hope I helped reassure you of your answer :)
Tanzania [10]3 years ago
4 0

Answer: There are 32 outcomes that are possible.

Step-by-step explanation:

Since we have given that

Number of sections in a spinner = 2

Number of times the spinner spun = 5

According to question,

if it spun for 5 times every time there are 2 possibility outcomes from  2 sections ,

i.e.

2\times 2\times 2\times 2\times 2\\\\=2^5\\\\=32

Hence, there are 32 outcomes that are possible.

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Solve by factorising x2 + 8x + 15 = 0
adelina 88 [10]

Answer:

x = - 3/2 thats the answer

6 0
2 years ago
-25-6= -25 + -6 = -31
VashaNatasha [74]

30 + 40 1- 40 = 69

Step-by-step explanation:

4 0
3 years ago
If the polynomials p(x)=2x³ +bx² +3x-5 and q(x)= x³+x² -4x-b leave the same remainder, when divided by x-2, prove that b = -13/5
Tju [1.3M]

Step-by-step explanation:

Lets first find the remainder when p(x) is divided by x-2

p(2)=2(2)³+b(2)²+3(2)-5

p(2)=16+4b+6-5

p(2)=4b+17

Now let's find the remainder when q(x) is divided by x-2

q(2)=(2)³+(2)²-4(2)-b

q(2)=8+4-8-b

q(2)=4-b

Now let's equate both of them

4b+17=4-b

4b+b=4-17

5b=-13

b=-13/5 as required

5 0
3 years ago
5th Grade Math
LUCKY_DIMON [66]
516 is the dividend, 3 is the divisor, 172 would be the quotient.

3 goes into 5 once with a 2 remainder, that 2 turns into 21 because of the 1 in 516 which 3 goes into seven times with a remainder of zero turning into 6, which 3 goes into twice, making the quotient 172.

172 times 3 is 516
6 0
4 years ago
May someone please help me
Neporo4naja [7]
I believe that is ten right?
7 0
3 years ago
Read 2 more answers
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