Answer:
v= 335 m/s
2∆t= 0.75 s
∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m
You get a more low sound.
Conversely, when the wavelength becomes shorter you get a more treble sound.
;-)
Answer:
Explanation:
The work done on the capacitor is equal to the difference in potential energy stored in the capacitor in two different cases.
The potential energy is given by the following formula:
where C can be calculated using the plate separation and area.
Therefore, the potential energy in the first case is
In the second case:
The permittivity of the air is very close to that of vacuum, which is 8.8 x 10^-12.
So, the difference in the potential energy is
You never gave us an answer, so therefore, we can't answer this question.