Answer:
really think I can see you soon then you can do to
Answer:
v = 27 m/s
Explanation:
To find the speed of cars after the collision you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.
After the collision both cars traveled together, then you have:
(1)
m1: mass of the Toyota = 3-ton = 3000 kg
m2: mass of the taxi = 2-ton = 2000kg
v1: speed of the Toyota before the collision = 45m/s
v2: speed of the car before the collision = 0 m/s (it is at rest)
v: speed of both cars after the collision = ?
You solve the equation (1) for v:
Next, you replace the values of the rest of the variables:
hence, just after the collision both cars have a speed of 27m/s
Answer:
Physical equilibrium is defined as the equilibrium which develops between different phases or physical properties. In these processes, there is no change in chemical composition. The following are some examples of Physical Equilibria: Solid-Liquid Equilibria. Please give me the brainliest answer?
:) Hoped this helped!!! Have a good day!!! <3
Lamina occupies x² + y² = 14y. Outside circle is x² + y² = 49
To find the mass of lamina, integrate given density function over the region
m = ∫∫D P(x, y) dA
Subtitute x = r cosФ and y = r sinФ in x² + y² = 14y
and x² + y² = 49
x² + y² = 14y
(r cosФ)² + ( rsinФ)² = 14(rsinФ)
r² = 14r sin Ф
x² +y² = 49
r² = 49
r = 7
Cntre mass (-x. -y)
-x= i/m ∫∫D xp(x,y) dA = 1/m∫∫ (r cosФ) p( r, Ф)r
dr dФ
-y = 1/m∫∫D yp(x, y) dA = 1/m ∫∫D (r sinФ) p(r, Ф) r drФ
where m = ∫∫D p(x, y) dA
Answer:
Explanation:
Height of the hose pipe is given as
horizontal distance is given as
angle of elevation is given as 35 degree with the horizontal
now we know that the horizontal distance moved is given as
now we have
also we have
so we have