Hey there!:
Molar mass MgCl2 = 95.211 g/mol
Volume of solution in liters:
570.0 mL / 1000 => 0.57 L
Number of moles:
n = M * V
n = 2.00 * 0.57 => 1.14 moles of MgCl2
Therefore:
1 mol MgCl2 --------------- 95.211 g
1.14 moles MgCl2 ---------- ??
mass of MgCl2 = 1.14 * 95.211
mass of MgCl2 = 108.54 g
Hope that helps!
Na2CO3 + 2Cl- ⇒ 2NaCl + CO3^-2
<span>
1 mole of Na2CO3 = 106 g </span>
<span>2 moles of NaCl = 2 x 58.4
= 116.8 g
</span>Na2CO3 would increase by 116.8 / 106 = 1.10 to form 2NaCl.
<span>0.4862 g x 1.10 = 0.515 grams of NaCl.
</span>
K2CO3 + 2Cl- ⇒ 2KCl + CO3^-2
<span>1 mole of K2CO3 = 138.2 g </span>
<span>2 moles of KCl = 149.1 </span>
<span>
K2CO3 would increase by </span>149.1 /138.2 = 1.079 <span>to form 2KCl
</span>
<span> 0.4862 x 1.079 = 0.5246 g</span>
The latent heat is correlated with energy as follows:
Q = mL
550 * 103 = 14 * 103 * L
L = 39.285 J /g
Thus, latent heat of the substance is 39.285 j /g
<h2>
Answer:</h2>
A). Increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.
<h2>
Explanation:</h2>
