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Rudik [331]
4 years ago
7

Which equations represent precipitation reactions?

Chemistry
1 answer:
viktelen [127]4 years ago
3 0

In a precipitation reaction, one of the product formed is an insoluble precipitate.

The given reactions can be written with phases included as:

A. Na_{2}S(aq)+FeBr_{2}(aq)-->2NaBr(aq)+FeS(s): In this reaction one of the product, FeS is insoluble. Therefore, this is a precipitation reaction.

B. MgSO_{4}(aq)+CaCl_{2}(aq)-->MgCl_{2}(aq)+CaSO_{4}(s): In this reaction, the product CaSO_{4}is a solid(insoluble). So, this is a precipitation reaction too.

C.LiOH(aq)+NH_{4}I(aq)-->LiI(aq)+NH_{4}OH(aq): In this reaction, both the products are soluble. So this is not a precipitation reaction.

D.2NaCl(aq)+K_{2}S(aq)-->Na_{2}S(aq)+2KCl(aq): In this reaction, both the products are soluble. So this is not a precipitation reaction.

E. AgNO_{3}(aq)+NaCl(aq)-->AgCl(s)+NaNO_{3}(aq): In this reaction, the product AgCl is a precipitate. So, it is a precipitation reaction.


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How do the chemical properties of the halegons compare to those of the noble gases
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Answer:

The halogens are extremely reactive, whilst the noble gases are mainly inert.

Only some noble gases tend to form compounds, such as xenon and krypton. However, some like helium, almost have no compounds at all. Noble gases also have octet rule shells, which causes the little reactivity associated with them. To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. Compounds like chlorine and fluorine must be stored carefully, as they will oxidise anything that they can find, just to get one extra electron to get an octet configuration.


Hope this helps :)

6 0
3 years ago
Read 2 more answers
6 How many moles are in a 321 g sample of magnesium?
Tatiana [17]

Answer:

13.4mol of Mg

Explanation:

Given parameters:

Mass of magnesium = 321g

Unknown:

Number of moles  = ?

Solution:

The number of moles of a substance is given as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of Mg = 24g/mol

 Insert the parameters and solve;

        Number of moles  = \frac{321}{24}   = 13.4mol of Mg

3 0
3 years ago
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kakasveta [241]

Gradpoint

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5 0
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boyakko [2]

Answer:

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Explanation:

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What ion the element P forms? Explain.
emmasim [6.3K]
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