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uysha [10]
2 years ago
6

On a distance-time graph, at 2 hours the graph is at a height of 20 meters, and at 3 hours it is at a height of 100 meters. What

is the average speed for the interval?
Chemistry
1 answer:
Gnoma [55]2 years ago
8 0

Answer:

80 m/hr

Explanation:

Changes from 20 to 100 meters in ONE Hour

    changes  80 meters in one hour    = 80 m/hr

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2Fe + 3C02<br> 3CO + Fe2O3<br> AH = -24.7 kJ<br> Is the reaction exothermic or endothermic?
Softa [21]

Answer:

the answer should be B xD<<<<<<<<<<<:::::::::::>>>>>>>>::::::::::::<<<<<<:::::>>>>>::::: makes this brainlist for good luck for the rest of ur life dont risk it

Explanation:

7 0
3 years ago
A sample of 0.3283 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of A
Pavel [41]

Answer:

92.49 %

Explanation:

We first calculate the number of moles n of AgBr in 0.7127 g

n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g

n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol

Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and

From n = m/M

m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol

m = 0.0038 mol × 79.904 g/mol = 0.3036 g

% Br in compound = m₁/m₂ × 100%

m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)

m₂ = mass of compound = 0.3283 g

% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %

4 0
3 years ago
copper forms two oxides. On heating 1 g of each in hydrogen 0.888 g and 0.798 g of the metal was obtained. Show that the results
Mashutka [201]

Answer:

For the first oxide, 1 g gives 0.888 g of copper.

Dividing by 0.888 tells us that 1.126 g gives 1 g of copper so has 0.126 g of oxygen.

For the second oxide, 1 g gives 0.798 g of copper.

Dividing by 0.798 tells us that 1.253 g gives 1 g of copper so has 0.253 g of oxygen.

So 1 g of copper combines with either 0.126 g or 0.253 g of oxygen.

Within the limits of experimental error, 0.253 is twice 0.126, confirming the law of multiple proportion.

6 0
2 years ago
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13. What does the Law of Conservation of Mass state?
Hoochie [10]
The law of conservation of mass states that mass can neither be created or destroyed in a chemical reaction.
5 0
3 years ago
What is the difference between measured and accepted value? And how are these values used to determine the precision of these va
serg [7]
Measured values are verified and go under a series of experiments before being accepted as the norm. Accepted values are unanimously accepted values, seen as the norm by a qualified group of individuals (scientists or the people of the intellectual sphere).
7 0
3 years ago
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