On a distance-time graph, at 2 hours the graph is at a height of 20 meters, and at 3 hours it is at a height of 100 meters. What
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Answer:
Explanation:
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In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:
Thus, we infer the hydrogen is the limiting reactant and therefore we use its 1:2 mole ratio with HCl whose molar mass is 36.46 g/mol:
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The composition of the stack gas are :
= 0.8713
= 0.0202
CO = 0.107
<h3 /><h3>What is a mole fraction?</h3>The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.
Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.
Mass of : 70% of 100 g = 70 g
Mass of : 15% of 100 g = 15 g
Mass of CO : 15% of 100 g = 15 g
Now calculate the number of moles of each species:
Number of moles of :
= 4.3 mole
Number of moles of :
= 0.10 mole
Mass of CO : = 0.53 mole
Now to calculate the mole fraction of each we use the formula:
Mole fraction of :
= 0.8713
Mole fraction of :
= 0.0202
Mole fraction of CO : = 0.107
Hence, composition of the stack gas are:
= 0.8713
= 0.0202
CO = 0.107
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Answer:
Explanation:
Hello there!
Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:
In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
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