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Anna007 [38]
2 years ago
13

What are things animals might do to survive?

Chemistry
1 answer:
ira [324]2 years ago
7 0

Answer:

Ok,for some animals to survive,then ww should first look at the kind of ecosystem they ate exposed to.

So first for some animals to survive,some of them will have to migrate,and so migration in a given set up of an ecosystem,the other animals may lack food as in they depend on the migrating animals as their prey hence their food.

Secondly,hibernation some animals may hibernate due to intensive weather or climate change which is inevitable,and this might affect other animals in such a way that may lead to decrease of their counterparts hence dying due to an imbalance as the other animals may become prey to the predators available.

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Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. Answer A: Reaction of hypochlorous acid and
pickupchik [31]

Answer:

A. True

B. False

Explanation:

Reaction between hypochlorous acid and ammonia does not yields a Ph value of 7.00 , this value is defined to water and no other reaction can yield exactly this Ph value. The acid reaction will give a Ph value below 7 while a base reaction will give Ph value of above 7.

7 0
2 years ago
The equation K + NaOH => Na + KOH should it react, true or false?
Andru [333]

Answer:

yes it should react yoyoyoyoyo

3 0
2 years ago
Number of electrons for all of these even the ones with a number by them ? Will give brainlist!!!!
Bumek [7]

Explanation:

s=2

p=6

d=10

f=14

pls mark me brainlist

7 0
2 years ago
A rigid tank contains 2.4 kg of helium at determine the volume
ddd [48]
The volume is 1.3 for
4 0
3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

3 0
3 years ago
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