4 and 5 are right, but 2 isn't because consonants are the opposite of vowels. So, you wouldn't use a or e.
The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.
The converse of a conditional statement switches the hypothesis and conclusion.
Look it up on the internet youll find the answer there i am only learining about adding integers right now