How do i draw these lines?

Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K

Virty [35]

Answer:

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

Explanation:

$Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_{f}^{o} = 12.0 kJ$

$\Delta G_{f,SnO_2}^{o}= -515.8kJ/mol$

$\Delta G_{f,Sn}^{o}= 0 kJ/mol$

$\Delta G_{f,SnO}^{o}=?$

$\Delta G_{f}^{o}=\sum ((\Delta G_{f}^{o})_ {products})-\sum ((\Delta G_{f}^{o})_ {reactants})$

$12.0 kJ=(2 mol\times \Delta G_{f,SnO}^{o})-(1mol\times 0 kJ/mol+1 mol\times -515.8 kJ/mol)$

$\Delta G_{f,SnO}^{o}=-251.9 kJ/mol$

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

3 0

3 years ago

Also need to know some of this stuff

irinina [24]

Answer:

answers are in attachment

Explanation:

1. Synthesis Reaction: In this type of reaction multiple reactant combine to form a single product.

2. Decomposition Reaction: In this type of reaction single compound or reactant break down into new elements or compounds.

3. Replacement Reaction: In this type of reaction an element replace an element in a compound.

4. Even hydrogen is not a metal but it can act as metal in single replacement reaction.

5. In combustion reaction fuel react with oxygen and give heat and light that increase temperature of surrounding.

6. In in-complete combustion reaction fuel react with in-sufficient oxygen and give carbon monoxide and carbon in form of soot.

7. Base is a compound that liberate OH⁻ ion in water.

8. indicators have different color in acid and base depends on pH of the solution

9. Salt and water are the product of neutralization reaction

NaOH + HCl = NaCl + H₂O

10. The pH of neutral solution is 7.

6 0

3 years ago

A. 207 kJ B. 4730 kJ O C. 9460 kJ O D. 414 kJ

slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg × 4730 Kj/Kg

Q = 9460 Kj

3 0

3 years ago

A sample of nitrogen gas is at a temperature of 50 c and a pressure of 2 atm. If the volume of the sample remains constant and t

Lilit [14]

Answer:

The new temperature of the nitrogen gas is 516.8 K or 243.8 C.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P = pressure, T = temperature, K = Constant

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

$\frac{P1}{T1} =\frac{P2}{T2}$