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Ad libitum [116K]
3 years ago
14

NEED HELP ASPA WILL MAKE THE BRAINIEST ANSWER

Chemistry
1 answer:
fomenos3 years ago
5 0

Answer: H_2 < CO < O_2 < CO_2 < CL_2

Explanation:

According to avogadro's law, 1 mole of every substanceweighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

1. Mass of H_2=moles\times {\text {Molar mass}}=0.50moles\times 2g/mol=1g

2. Mass of O_2=moles\times {\text {Molar mass}}=0.50moles\times 32g/mol=16g

3. Mass of Cl_2=moles\times {\text {Molar mass}}=0.50moles\times 71g/mol=35.5g

4. Mass of CO_2=moles\times {\text {Molar mass}}=0.50moles\times 44g/mol=22g

5. Mass of CO=moles\times {\text {Molar mass}}=0.50moles\times 28g/mol=14g

Thus the flasks of gases in order of increasing grams of gas is:

H_2 < CO < O_2 < CO_2 < CL_2

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lesya692 [45]

Answer:

a) grams of this impurity per kg of CCl4 = 3.416 g/kg of solvent.

b) mass purity % = 99.66%

Explanation:

Given, the freezing point of pure CCl₄ = - 23°C

Presence of impurities lowers the freezing point to - 23.43°C

The freezing point depression constant, Kբ = 29.8°C/m

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ΔT = i Kբ × m

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i = Van't Hoff factor which measures how much the impurities influence/affect colligative properties (such as freezing point depression) and for most non-electrolytes like this one, it is = 1

Kբ = The freezing point depression constant = 29.8°C/m

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T⁰ - T = i Kբ m

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Them we're told to calculate impurity of the CCl₄

we convert the Molality to (gram of solute)/(kg of solvent) first

Solute = C₂Cl₆

Molar mass = 236.74 g/mol

So, (molality × molar mass) = (gram of solute)/(kg of solvent)

(gram of solute)/(kg of solvent) = 0.0144 × 236.74 = 3.416 (gram of solute)/(kg of solvent)

Mass purity % = (1000 g of pure substance)/(1000 g of pure substance + mass of impurity in 1000 g of pure substance)

1000 g of solvent contains 3.416 grams of impurities

Mass purity % =100% × 1000/(1003.416)

Mass purity % = 99.66 %

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